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Chapter 12, Problem 17Q
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### Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

#### Solutions

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Section
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### Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

# The initial rate of a reaction doubles as the concentration of one of the reactants is quadrupled. What is the order of this reactant? If a reactant has a −1 order, what happens to the initial rate when the concentration of that reactant increases by a factor of two?

Interpretation Introduction

Interpretation: It is given that, the initial rate of a reaction doubles as the concentration of one of the reactants is quadrupled. The order of this reaction is to be stated. If a reactant has a 1 order, the initial rate is to be calculated when the concentration of that reactant increases by a factor of two.

Concept introduction: The change observed in the concentration of a reactant or a product per unit time is known as the rate of the particular reaction. The differential rate law provides the rate of a reaction at specific reaction concentrations.

To determine: The order of the reaction if the initial rate of a reaction doubles as the concentration of one of the reactants is quadrupled; the initial ratewhen the concentration of that reactant increases by a factor of two and the order of reactant is 1 .

Explanation

The order of the reaction is 12_ .

The rate law gives the relation between reaction rate and concentration of reactants. The rate law is represented as,

Rate=k[A]a[B] (1)

Where,

• k is rate constant.
• [A] is concentration of reactant A .
• [B] is concentration of reactant B .
• a is reaction order of A .

The initial rate of a reaction doubles as the concentration of one of the reactants is quadrupled. The above equation becomes,

2×Rate=k[4A]a[B] (2)

Divide equation (1) and (2)

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