Chapter 12, Problem 18PS

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# Calculate the lattice enthalpy for RbCl. In addition to data in Appendices F and L, you will need the following information;     Δ f H ° [Rb(g)] = 80 .9 kJ/mol Δ f H ° [RbCl(s)] =  − 435 .4 kJ/mol TABLE 12.1Lattice Energies of Some Ionic Compounds

Interpretation Introduction

Interpretation:

The lattice enthalpy of rubidium chloride has to be calculated.

Concept introduction:

The lattice enthalpy is calculated by using following method,

ΔHof(RbCl)=ΔH at(Rb)+ΔH at(Cl)+ΔHIE(Rb)+ΔHEA(Cl)+ΔHlattice(RbCl)

Explanation

The molar enthalpy formation is calculated by using Hess law, the enthalpy of the formation is given below

Î”Hof(RbCl)â€‰=â€‰Î”HÂ at(Rb)â€‰+â€‰Î”HÂ at(Cl)+â€‰Î”HIE(Rb)â€‰+Î”HEA(Cl)+â€‰Î”Hâ€‰lattice(RbCl)Î”Hof(RbCl)=â€‰-435.4kJ/molÎ”HÂ at(Rb)â€‰=â€‰+80.9kJ/molâ€‰Î”HÂ at(Cl)â€‰=â€‰+121kJ/molÎ”HIE(Rb)â€‰â€‰=â€‰+403â€‰kJ/molÎ”HEA

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