   Chapter 12, Problem 1P

Chapter
Section
Textbook Problem

An ideal gas is enclosed in a cylinder with a movable piston on top of it. The piston has a mass of 8.00 × 103g and an area of 5.00 cm2 and is free to slide up and down, keeping the pressure of the gas constant. (a) How much work is done on the gas as the temperature of 0.200 mol of the gas is raised from 20.0°C to 3.00 × 102°C? (b) What does the sign of your answer to part (a) indicate?

(a)

To determine
The work done on the ideal gas.

Explanation

Section1:

To determine: To determine the work done on ideal gas.

Solution: The work done on the gas is 465.36J .

Explanation:

Given Info:

Mass of the piston is 8×103g

Area of the piston is 5cm2

Volume of the gas is 0.2 mol

Temperature of the ideal gas changes from 200C to 3×1020C .

Formula to calculate the work done on the gas in the constant pressure process is,

W=nR(TfTi)

• n is the number of moles
• R is the gas constant
• Tf is the  finial temperature
• Ti

(b)

To determine
the significance of sign of work done in Section 1.

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