
Fundamentals of Physics Extended
10th Edition
ISBN: 9781118230725
Author: David Halliday, Robert Resnick, Jearl Walker
Publisher: Wiley, John & Sons, Incorporated
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Textbook Question
Chapter 12, Problem 20P
A bowler holds a bowling ball (M = 7.2 kg) in the palm of his hand (Fig. 12-37). His upper arm is vertical; his lower arm (1.8 kg) is horizontal. What is the magnitude of (a) the force of the biceps muscle on the lower arm and (b) the force between the bony structures at the elbow contact point?
Figure 12-37 Problem 20.
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a vertical uniform beam of length Lthat is hinged at its lower end.A horizontal force F is applied to the beam at distance y from the lower end. The beam remainsvertical because of a cable attached at the upper end, at angle uwith the horizontal. gives the tension T in the cableas a function of the position of the applied force given as a fractiony/L of the beam length.The scale of the T axis is set by Ts= 600 N.Figure 12-49c gives the magnitude Fh of the horizontal force on thebeam from the hinge, also as a function of y/L. Evaluate (a) angle uand (b) the magnitude of .
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Chapter 12 Solutions
Fundamentals of Physics Extended
Ch. 12 - Figure 12-15 shows three situations in which the...Ch. 12 - In Fig, 12-16, a rigid beam is attached to two...Ch. 12 - Figure 12-17 shows four overhead views of rotating...Ch. 12 - A ladder leans against a frictionless wall but is...Ch. 12 - Figure 12-18 shows a mobile of toy penguins...Ch. 12 - Figure 12-19 shows an overhead view of a uniform...Ch. 12 - In Fig. 12-20, a stationary 5 kg rod AC is held...Ch. 12 - Three piatas hang from the stationary assembly of...Ch. 12 - In Fig. 12-22, a vertical rend is hinged at its...Ch. 12 - Figure 12-23 shows a horizontal block that is...
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T= In N
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A uniform horizontal beam 5.00 m long and weighting 3.03  102 N is attached to a wall by a pin connection that allows the beam to rotate. Its far end is supported by a cable that makes an angle of 53.0° with the horizontal (Figure (a)). If a person weighing 6.05  102 N stands 1.60 m from the wall, find the magnitude of the tension  in the cable and the force  exerted by the wall on the beam.
T
=Â Â N
Rx
=Â Â N
Ry
=Â Â N
Â
Even if we selected some other axis for the torque equation, the solution would be the same. For example, if the axis were to pass through the center of gravity of the beam, the torque equation would involve both T and Ry. Together with Equations (1) and (2), however, the unknowns could still be found—a good exercise. In this example, notice the steps of the Problem-Solving Strategy could be carried out in the explicit recommended order.QUESTION What happens to the tension in the cable if the man in Figure (a) moves farther away from the wall?
The tension would…
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