   # The following equilibrium pressures at a certain temperature were observed for the reaction 2 NO 2 ( g ) ⇌ 2 NO ( g ) + O 2 ( g ) P NO 2 = 0.55 atm P NO = 6.5 × 10 − 5 atm P O 2 = 4.5 × 10 − 5 atm Calculate the value for the equilibrium constant K p at this temperature. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 12, Problem 29E
Textbook Problem
1 views

## The following equilibrium pressures at a certain temperature were observed for the reaction 2 NO 2 ( g ) ⇌ 2 NO ( g ) + O 2 ( g ) P NO 2 = 0.55   atm P NO     = 6.5 × 10 − 5 atm P O 2       = 4.5 × 10 − 5 atm Calculate the value for the equilibrium constant Kp at this temperature.

Interpretation Introduction

Interpretation: The partial pressure values of NO2 , NO and O2 at a particular temperature are given. The value of the equilibrium constant (Kp) for the given reaction is to be calculated.

Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction. When the equilibrium constant is expressed in terms of pressure, it is represented Kp .

To determine: The equilibrium constant (Kp) for the given reaction.

### Explanation of Solution

Given

The stated reaction is,

2NO2(g)2NO(g)+O2(g)

The partial pressure value for NO2 (PNO2) is 0.55atm .

The partial pressure value for NO (PNO) is 6.5×105atm .

The partial pressure value for O2 (PO2) is 4.5×105atm .

At equilibrium, the equilibrium ratio is expressed by the formula,

Kp=PartialpressureofproductsPartialpressureofreactants

Where,

• Kp is the equilibrium constant in terms of partial pressure

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts
Which of the following energy systems provides the needed energy for a lifters heave of a heavyweight? the aero...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

13-4 Define aromatic compound.

Introduction to General, Organic and Biochemistry

What are genomes?

Human Heredity: Principles and Issues (MindTap Course List)

Explain how Kapler’s lows contradict uniform circular motion.

Horizons: Exploring the Universe (MindTap Course List)

When a high-power laser is used in the Earths atmosphere, the electric field associated with the laser beam can...

Physics for Scientists and Engineers, Technology Update (No access codes included)

Why do expanding, aging stars become cooler and more luminous?

Foundations of Astronomy (MindTap Course List)

Why do you think the mid-ocean ridges are higher than the surrounding seabed?

Oceanography: An Invitation To Marine Science, Loose-leaf Versin 