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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 12, Problem 37E
Textbook Problem
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What is the molarity of a solution that contains 15 g of KCl in 325 mL of solution?

Interpretation Introduction

Interpretation:

The molarity of KCl solution with given mass and volume of solution is to be determined.

Concept Introduction:

Molarity is defined as the number of moles of solute per liter of solution. Mathematically, molarity (M) is calculated as:

Molarity(M)=Moles soluteLiters solution

The volume of solution should be in liters and the unit of molarity is M.

The relation between the numbers of moles (n) and molar mass is:

n=mmolar mass

The relationship between liters and milliliters can be expressed as: 1 mL=103 L

To convert milliliters (mL) to liters (L), conversion factor is (103 L1 mL)

The molar mass of KCl is calculated as:

Molar mass of KCl= atomic mass of K + atomic mass of Cl

Explanation of Solution

Given information:

Mass of KCl is 15 g and volume of solution is 325 mL.

The molar mass of KCl is calculated as:

Molar mass of KCl=(39+35.5)(1g/mol)=74.5 g/mol

The number of moles and molar mass is related as;

n=mmolar mass

Substitute 15 g for m and 74.5 g/mol for the molar mass in the above expression as follows:

n=15 g74.5 g/mol=0

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Chemistry In Focus
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