   Chapter 12, Problem 3P

Chapter
Section
Textbook Problem

Gas in a container is at a pressure of 1.5 atm and a volume of 4.0 m3. What is the work done on the gas (a) if it expands at constant pressure to twice its initial volume, and (b) if it is compressed at constant pressure to one-quarter its initial volume?

(a)

To determine
The work done on the gas if it expands at constant pressure to twice its initial volume.

Explanation

Given Info:

Constant pressure of the gas is (1.5atm)(1.013×105Pa/atm) .

Volume of the gas in the container is 4m3 .

Formula to calculate the work done of the gas is,

W=P(ΔV)

• P is the pressure.
• ΔV Is the change in volume.

When the gas expands at constant pressure to twice its initial volume, ΔV is equals to ΔV=+4m3 .

Substitute (1.5atm)(1

(b)

To determine
The work done on the gas if it compressed at constant pressure to one-quarter its initial volume.

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