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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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Section
BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 12, Problem 42E
Textbook Problem
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How many grams of NaF are present in 4.5 L of a 1 .1% NaF solution by mass? Assume that the density of the solution is 1.0 g/mL.

Interpretation Introduction

Interpretation:

The mass of NaF in a given solution is to be calculated.

Concept Introduction:

The same solute and solvent can form a number of combinations by varying their amounts. These combinations can be differentiated in terms of concentration of solution. The amount of a solute present in a given amount of a solvent is defined as its concentration.

Mass percent is defined as the mass of a solute present in 100 g of a solution.

Density is the ratio of the mass of a substance to its volume.

A mole is a unit of amount of a substance. It relates the number of particles to molar mass.

Density of a solution as presented as:

Density=Mass of solutionVolume of solution

As 1 L is equal to 1000 mL, hence the conversion factor will be as:

1000mL1L

Mass percent of compound=Mass of compoundMass of solution

Explanation of Solution

Given Information: The solution of NaF is 1.1% of the solution by mass. The volume of the solution is 4.5 L. The density of the solution is 1.0 g/mL.

The mass of the solution is calculated using formula of density as:

Density=Mass of solutionVolume of solution ….(1)

As the density is in g/mL, the volume is converted to from L to mL using conversion factor as:

1 L=1000 mL4.5 L=1000 mL1 L×4.5 L=4500 mL

Substitute the given values in the above equation (1) as:

1.0 g/mL=Mass of solution4500 mL Mass of solution=1

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Chemistry In Focus
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