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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

In one cycle a heat engine absorbs 500 J from a high-temperature reservoir and expels 300 J to a low-temperature reservoir. If the efficiency of this engine is 60% of the efficiency of a Carnot engine, what is the ratio of the low temperature to the high temperature in the Carnot engine?

To determine
The ratio of the low temperature to the high temperature in the Carnot engine.

Explanation

Section1:

To determine: The actual efficiency of the engine.

Solution: The actual efficiency of the heat engine is 0.400 .

Explanation:

Given Info:

The energy, the heat engine absorbs from the hot reservoir is 500J

The energy, the heat engine release to cold reservoir is 300J

Formula to calculate the efficiency of the engine,

e=1QcQh

  • Qc is the energy expelled to the cold reservoir
  • Qh is the energy absorbed from the hot reservoir

Substitute 500J for Qh and 300J for Qc to find the actual efficiency,

e=1300J500J=0.400

Thus, the actual efficiency of the heat engine is 0.400 .

Conclusion:

From section1, the actual efficiency of the heat engine is 0.400 .

The efficiency of the heat engine is 60% of the Carnot engine

Thus,

ec=e0

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