   # A softened water sample contains 245 ppm Na. If a person consumes 1 .5 L of this water per day, how many mg of sodium are consumed? ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

#### Solutions

Chapter
Section ### Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 12, Problem 46E
Textbook Problem
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## A softened water sample contains 245 ppm Na. If a person consumes 1 .5 L of this water per day, how many mg of sodium are consumed?

Interpretation Introduction

Interpretation:

The mass of sodium (in mg) consumed is to be calculated.

Concept Introduction:

Solutions are homogeneous mixtures made up of two components, the solute and the solvent.

The same solutes and solvents can form a number of combinations by varying their amounts. These combinations can be differentiated in terms of concentration of solutions. Concentration of a solution is defined as the amount of solute present in the given amount of solvent.

There are many ways of expressing concentration of a solution, such as mass percent, volume percent, molarity, parts per million.

Mass percent is defined as the mass of solute present in 100 g of a solution.

Volume percent is defined as the mass of solute present in 100 mL of a solution.

Parts per million is defined as the mass of solute present in 106 g of a solution. It is used for expressing concentration when a small amount of solute is present in the solution.

Density  = Mass of water (g)Volume of water (L)

It is known 1 g = 1000 mg, conversion factor is as 1000 mg1 g

### Explanation of Solution

Given Information: Concentration of sodium in water is 245 ppm.

Mass of water sample is 1.5 L.

Assuming that the density of water is 1 g/mL or 1000 g/L.

The mass of water sample is calculated as follows:

Density (g/L) = Mass of water (g)Volume of water (L)Mass of water (g) = Density of water (g/L) ×Volume of water (L)

Substitute the given values in the above equation as:

Mass of water (g) = 1000 g/L ×1.5 LMass of water (g) = 1500 g

The mass of sodium is calculated as follows:

Concentration of sodium (ppm) = Mass of sodium (g)Mass of water (g)× 106ppm

Substitute the value in the above equation as follows:

245 ppm = Mass of sodium (g)1500

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