Chapter 12, Problem 55QAP

### Chemistry: Principles and Reactions

8th Edition
William L. Masterton + 1 other
ISBN: 9781305079373

Chapter
Section

### Chemistry: Principles and Reactions

8th Edition
William L. Masterton + 1 other
ISBN: 9781305079373
Textbook Problem

# Iodine chloride decomposes at high temperatures to iodine and chlorine gases. 2 ICl ( g ) ⇌ I 2 ( g ) +Cl 2 ( g ) Equilibrium is established at a certain temperature when the partial pressures of ICl, I2, and Cl2 are (in atm) 0.43, 0.16, and 0.27, respectively.(a) Calculate K.(b) If enough iodine condenses to decrease its partial pressure to 0.10 atm, in which direction will the reaction proceed? What is the partial pressure of iodine when equilibrium is reestablished?

Interpretation Introduction

(a)

Interpretation:

The equilibrium constant for the reaction at given temperature needs to be determined.

Concept introduction:

The system is said to be in equilibrium if the there is no change in the partial pressure or concentration of reactant and product takes place.

For a general equilibrium reaction as follows:

A(g)+B(g)C(g)+D(g)

The expression for the equilibrium constant is represented as follows:

K=(PC)(PD)(PA)(PB)

Here, to calculate the equilibrium constant, the values of partial pressure of all the species in reactant and product side are required.

Explanation

The equilibrium reaction is as follows:

2ICl(g)â‡ŒI2(g)+Cl2(g)

The partial pressures of ICl, I2 and Cl2 is 0.43, 0.16 and 0.27 respectively.

The equilibrium constant for the reaction can be calculated as follows:

K=(PI2</

Interpretation Introduction

(b)

Interpretation:

The partial pressure of iodine when equilibrium is established needs to be determined.

Concept introduction:

The system is said to be in equilibrium if the there is no change in the partial pressure or concentration of reactant and product takes place.

For a general equilibrium reaction as follows:

A(g)+B(g)C(g)+D(g)

The expression for the equilibrium constant is represented as follows:

K=(PC)(PD)(PA)(PB)

Here, to calculate the equilibrium constant, the values of partial pressure of all the species in reactant and product side are required.

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