BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.2, Problem 58E
To determine

To simplify: the given expression.

Expert Solution

Answer to Problem 58E

  a2b364a4b3=4a2b23

Explanation of Solution

Given information:

Given expression

  a2b364a4b3

Calculation:

Consider the given expression.

  a2b364a4b3

Use the law of exponents amn=amn , (ab)m=ambm and aman=am+n

So, the expression can be simplified as

  a2b364a4b3=(a2b)13(64a4b)13=(64a2+6b1+1)13=(64a6b2)13=(64)13(a6)13(b2)13=(43)13(a6)13(b2)13=433a63b23=4a2b23

Hence, a2b364a4b3=4a2b23 .

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