# the given expression ( 8 y 3 ) − 2 3 .

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.2, Problem 64E

(a)

To determine

## To simplify: the given expression (8y3)−23 .

Expert Solution

(8y3)23=14y2

### Explanation of Solution

Given information:

Given expression

(8y3)23

Calculation:

Consider the given expression.

(8y3)23

Now, use the law of exponents, which states

(am)n=amn

And combine like terms

(8y3)23=(23y3)23=[(2y)3]23=(2y)3×(23)=(2y)2=14y2 [an=1an]

Hence,

(8y3)23=14y2

(b)

To determine

### To simplify: the given expression (u4v6)−13 .

Expert Solution

(u4v6)13=1u43v2

### Explanation of Solution

Given information:

Given expression

(u4v6)13

Calculation:

Consider the given expression.

(u4v6)13

Now, use the law of exponents, which states

(am)n=amn

And combine like terms

(u4v6)13=(u4)13×(v6)13=u4×(13)×v6×(13)=u43×v2=1=u43v2 [an=1an]

Hence,

(u4v6)13=1u43v2

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