BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.2, Problem 64E

(a)

To determine

To simplify: the given expression (8y3)23 .

Expert Solution

Answer to Problem 64E

  (8y3)23=14y2

Explanation of Solution

Given information:

Given expression

  (8y3)23

Calculation:

Consider the given expression.

  (8y3)23

Now, use the law of exponents, which states

  (am)n=amn

And combine like terms

  (8y3)23=(23y3)23=[(2y)3]23=(2y)3×(23)=(2y)2=14y2 [an=1an]

Hence,

  (8y3)23=14y2

(b)

To determine

To simplify: the given expression (u4v6)13 .

Expert Solution

Answer to Problem 64E

  (u4v6)13=1u43v2

Explanation of Solution

Given information:

Given expression

  (u4v6)13

Calculation:

Consider the given expression.

  (u4v6)13

Now, use the law of exponents, which states

  (am)n=amn

And combine like terms

  (u4v6)13=(u4)13×(v6)13=u4×(13)×v6×(13)=u43×v2=1=u43v2 [an=1an]

Hence,

  (u4v6)13=1u43v2

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