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PhysicsCollege Physics11th Edition

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Chapter 12, Problem 74AP
BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Solutions

Chapter
Section
Problem 1CQ
Problem 2CQ
Problem 3CQ
Problem 4CQ
Problem 5CQ
Problem 6CQ
Problem 7CQ
Problem 8CQ
Problem 9CQ
Problem 10CQ
Problem 11CQ
Problem 12CQ
Problem 13CQ
Problem 14CQ
Problem 15CQ
Problem 16CQ
Problem 17CQ
Problem 1P
Problem 2P
Problem 3P
Problem 4P
Problem 5P
Problem 6P
Problem 7P
Problem 8P
Problem 9P
Problem 10P
Problem 11P
Problem 12P
Problem 13P
Problem 14P
Problem 15P
Problem 16P
Problem 17P
Problem 18P
Problem 19P
Problem 20P
Problem 21P
Problem 22P
Problem 23P
Problem 24P
Problem 25P
Problem 26P
Problem 27P
Problem 28P
Problem 29P
Problem 30P
Problem 31P
Problem 32P
Problem 33P
Problem 34P
Problem 35P
Problem 36P
Problem 37P
Problem 38P
Problem 39P
Problem 40P
Problem 41P
Problem 42P
Problem 43P
Problem 44P
Problem 45P
Problem 46P
Problem 47P
Problem 48P
Problem 49P
Problem 50P
Problem 51P
Problem 52P
Problem 53P
Problem 54P
Problem 55P
Problem 56P
Problem 57P
Problem 58P
Problem 59P
Problem 60P
Problem 61P
Problem 62AP
Problem 63AP
Problem 64AP
Problem 65AP
Problem 66AP
Problem 67AP
Problem 68AP
Problem 69AP
Problem 70AP
Problem 71AP
Problem 72AP
Problem 73AP
Problem 74AP
Problem 75AP
Problem 76AP
BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

Hydrothermal vents deep on the ocean floor spout water at temperatures as high as 570°C. This temperature is below the boiling point of water because of the immense pressure at that depth. Because the surrounding ocean temperature is at 4.0°C, an organism could use the temperature gradient as a source of energy. (a) Assuming the specific heat of water under these conditions is 1.0 cal/g · °C, how much energy is released when 1.0 L of water is cooled from 570°C to 4.0°C? (b) What is the maximum usable energy an organism can extract from this energy source? (Assume the organism has some internal type of heat engine acting between the two temperature extremes.) (c) Water from these vents contains hydrogen sulfide (H2S) at a concentration of 0.90 mmole/L. Oxidation of 1.0 mole of H2S produces 310 kJ of energy. How much energy is available through H2S oxidation of 1.0 L of water?

(a)

To determine
The energy released from water when it cools.

Explanation

Given Info:

High temperature of the water is 570 °C .

Low temperature of the water is 4.0 °C .

Specific heat of the water is 1.0 cal/g⋅°C .

The amount of water cooled is 1.0 L

Formula to calculate the energy released from water is,

Qh=mc(ΔT) (I)

  • ΔT is the change in temperature
  • m is the mass of the water
  • c is the specific heat

Since, m=ρV

Equation (I) gives,

Qh=(ρV)c(ΔT)

  • ρ is the density of water
  • V is the volume of water

Substitute 566 °C for ΔT , 1.0 cal/g⋅°C for c, 1 g/cm3 for ρ and 1

(b)

To determine
The maximum usable energy an organism can extract from this energy source.

(c)

To determine
The energy available through H2S oxidation of 1.0 L of water.

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Sect-12.1 P-12.1QQSect-12.3 P-12.2QQSect-12.4 P-12.3QQSect-12.5 P-12.4QQSect-12.5 P-12.5QQCh-12 P-1CQCh-12 P-2CQCh-12 P-3CQCh-12 P-4CQCh-12 P-5CQ
Ch-12 P-6CQCh-12 P-7CQCh-12 P-8CQCh-12 P-9CQCh-12 P-10CQCh-12 P-11CQCh-12 P-12CQCh-12 P-13CQCh-12 P-14CQCh-12 P-15CQCh-12 P-16CQCh-12 P-17CQCh-12 P-1PCh-12 P-2PCh-12 P-3PCh-12 P-4PCh-12 P-5PCh-12 P-6PCh-12 P-7PCh-12 P-8PCh-12 P-9PCh-12 P-10PCh-12 P-11PCh-12 P-12PCh-12 P-13PCh-12 P-14PCh-12 P-15PCh-12 P-16PCh-12 P-17PCh-12 P-18PCh-12 P-19PCh-12 P-20PCh-12 P-21PCh-12 P-22PCh-12 P-23PCh-12 P-24PCh-12 P-25PCh-12 P-26PCh-12 P-27PCh-12 P-28PCh-12 P-29PCh-12 P-30PCh-12 P-31PCh-12 P-32PCh-12 P-33PCh-12 P-34PCh-12 P-35PCh-12 P-36PCh-12 P-37PCh-12 P-38PCh-12 P-39PCh-12 P-40PCh-12 P-41PCh-12 P-42PCh-12 P-43PCh-12 P-44PCh-12 P-45PCh-12 P-46PCh-12 P-47PCh-12 P-48PCh-12 P-49PCh-12 P-50PCh-12 P-51PCh-12 P-52PCh-12 P-53PCh-12 P-54PCh-12 P-55PCh-12 P-56PCh-12 P-57PCh-12 P-58PCh-12 P-59PCh-12 P-60PCh-12 P-61PCh-12 P-62APCh-12 P-63APCh-12 P-64APCh-12 P-65APCh-12 P-66APCh-12 P-67APCh-12 P-68APCh-12 P-69APCh-12 P-70APCh-12 P-71APCh-12 P-72APCh-12 P-73APCh-12 P-74APCh-12 P-75APCh-12 P-76AP

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