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A common type of reaction we will study is that having a very small K value ( K << 1). Solving for equilibrium concentrations in an equilibrium problem usually requires many mathematical operations to be perfomed. However, the math involved when solving equilibrium problems for reactions having small K values (K << 1) is simplified. What assumption is made when solving the equilibrium concentrations for reactions with small K values? Whenever assumptions are made, they must be checked for validity. In general, the “5% rule” is used to check the validity of assuming x (or 2 x , 3 x, and so on) is very small compared to some number. When x (or 2 x . 3x. and so on) is less than 5% of the number the assumption was made against, then the assumption is said to be valid. If the 5% rule fails, what do you do to solve for the equilibrium concentrations?

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 12, Problem 8RQ
Textbook Problem
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A common type of reaction we will study is that having a very small K value (K << 1). Solving for equilibrium concentrations in an equilibrium problem usually requires many mathematical operations to be perfomed. However, the math involved when solving equilibrium problems for reactions having small K values (K << 1) is simplified. What assumption is made when solving the equilibrium concentrations for reactions with small K values? Whenever assumptions are made, they must be checked for validity. In general, the “5% rule” is used to check the validity of assuming x (or 2 x, 3x, and so on) is very small compared to some number. When x (or 2 x. 3x. and so on) is less than 5% of the number the assumption was made against, then the assumption is said to be valid. If the 5% rule fails, what do you do to solve for the equilibrium concentrations?

Interpretation Introduction

Interpretation: It is given that for a common type of reaction the value of K<<1 . The assumption made when solving the equilibrium concentrations for reactions with small K values and the procedure followed if the ‘ 5% rule’ fails are to be stated.

Concept introduction: If the error in the equilibrium concentration calculated is less than 5% , the assumption made is stated to be correct. This is known as the ‘ 5% rule’. If the error exceeds the 5% value, then the quadratic formula is used for calculating the equilibrium concentrations.

To determine: The assumption made when solving the equilibrium concentrations for reactions with small K values and the procedure followed if the ‘ 5% rule’ fails.

Explanation of Solution

On solving the equilibrium concentrations for reactions with small K values, the change in the reactant concentration is taken as negligible. This is the assumption made in solving these kinds of problems

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Chapter 12 Solutions

Chemistry: An Atoms First Approach
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Ch. 12 - Consider an equilibrium mixture of four chemicals...Ch. 12 - The boxes shown below represent a set of initial...Ch. 12 - For the reactionH2(g)+I2(g)2HI(g), consider two...Ch. 12 - Given the reactionA(g)+B(g)C(g)+D(g), consider the...Ch. 12 - Consider the reaction A(g)+2B(g)C(g)+D(g) in a...Ch. 12 - Consider the reactionA(g)+B(g)C(g)+D(g). A friend...Ch. 12 - Consider the following statements: Consider the...Ch. 12 - Le Chteliers principle is stated (Section 12-7) as...Ch. 12 - The value of the equilibrium constant K depends on...Ch. 12 - Consider an initial mixture of N2 and H2 gases...Ch. 12 - Consider the following reaction:...Ch. 12 - Consider the same reaction as in Question 11. In...Ch. 12 - Suppose a reaction has the equilibrium constant K...Ch. 12 - Suppose a reaction has the equilibrium constant K...Ch. 12 - Consider the following reaction at some...Ch. 12 - Consider the following generic reaction:...Ch. 12 - Explain the difference between K, Kp, and Q.Ch. 12 - Consider the following reactions:...Ch. 12 - For a typical equilibrium problem, the value of K...Ch. 12 - Which of the following statements is(are) true?...Ch. 12 - Write the equilibrium expression (K) for each of...Ch. 12 - Write the equilibrium expression (Kp) for each...Ch. 12 - At a given temperature, K = 1.3 102 for the...Ch. 12 - For the reaction H2(g)+Br2(g)2HBr(g) Kp = 3.5 104...Ch. 12 - For the reaction 2NO(g)+2H2(g)N2(g)+2H2O(g) it is...Ch. 12 - At high temperatures, elemental nitrogen and...Ch. 12 - At a particular temperature, a 3.0-L flask...Ch. 12 - At a particular temperature a 2.00-L flask at...Ch. 12 - The following equilibrium pressures at a certain...Ch. 12 - The following equilibrium pressures were observed...Ch. 12 - At 327c, the equilibrium concentrations are...Ch. 12 - At 1100 K, Kp = 0.25 for the reaction...Ch. 12 - Write expressions for K and Kp for the following...Ch. 12 - Write expressions for Kp for the following...Ch. 12 - For which reactions in Exercise 33 is Kp equal to...Ch. 12 - For which reactions in Exercise 34 is Kp equal to...Ch. 12 - Consider the following reaction at a certain...Ch. 12 - In a study of the reaction...Ch. 12 - The equilibrium constant is 0.0900 at 25C for the...Ch. 12 - The equilibrium constant is 0.0900 at 25C for the...Ch. 12 - At 900c, Kp = 1.04 for the reaction...Ch. 12 - Ethyl acetate is synthesized in a nonreacting...Ch. 12 - For the reaction 2H2O(g)2H2(g)+O2(g) K = 2.4 103...Ch. 12 - The reaction 2NO(g)+Br2(g)2NOBr(g) has Kp = 109 at...Ch. 12 - A 1.00-L flask was filled with 2.00 moles of...Ch. 12 - A sample of S8(g) is placed in an otherwise empty...Ch. 12 - At a particular temperature, 12.0 moles of SO3 is...Ch. 12 - At a particular temperature, 8.0 moles of NO2 is...Ch. 12 - An initial mixture of nitrogen gas and hydrogen...Ch. 12 - Nitrogen gas (N2) reacts with hydrogen gas (H2) to...Ch. 12 - At a particular temperature, K = 3.75 for the...Ch. 12 - At a particular temperature, K = 1.00 102 for the...Ch. 12 - At 2200C, Kp = 0.050 for the reaction...Ch. 12 - At 25c, K = 0.090 for the reaction...Ch. 12 - At 1100 K, KP = 0.25 for the reaction...Ch. 12 - At a particular temperature, Kp = 0.25 for the...Ch. 12 - At 35C, K = 1.6 105 for the reaction...Ch. 12 - At o particular temperature, K = 4 .0 107 for the...Ch. 12 - At a particular temperature, K = 2.0 106 for the...Ch. 12 - Lexan is a plastic used to make compact discs,...Ch. 12 - At 25C, Kp. = 2.9 103 for the reaction...Ch. 12 - A sample of solid ammonium chloride was placed in...Ch. 12 - Suppose the reaction system...Ch. 12 - Predict the shift in the equilibrium position that...Ch. 12 - An important reaction in the commercial production...Ch. 12 - What will happen to the number of moles of SO3 in...Ch. 12 - In which direction will the position of the...Ch. 12 - Hydrogen for use in ammonia production is produced...Ch. 12 - Old-fashioned smelling salts consist of ammonium...Ch. 12 - Ammonia is produced by the Haber process, in which...Ch. 12 - Calculate a value for the equilibrium constant for...Ch. 12 - Given the following equilibrium constants at...Ch. 12 - Consider the decomposition of the compound C5H6O3...Ch. 12 - At 25C. Kp 1 1031 for the reaction a. Calculate...Ch. 12 - The gas arsine, AsH3, decomposes as follows:...Ch. 12 - At a certain temperature, K = 9.1 10-4 for the...Ch. 12 - At a certain temperature, K = 1.1 l03 for the...Ch. 12 - For the reaction PCl5(g)PCl3(g)+Cl2(g) at 600. K,...Ch. 12 - At 25C, gaseous SO2Cl2 decomposes to SO2(g) and...Ch. 12 - For the following reaction at a certain...Ch. 12 - Novelty devices for predicting rain contain...Ch. 12 - Consider the reaction Fe3+(aq)+SCN(aq)FeSCN2+(aq)...Ch. 12 - Chromium(VI) forms two different oxyanions, the...Ch. 12 - The synthesis of ammonia gas from nitrogen gas and...Ch. 12 - Suppose K = 4.5 103 at a certain temperature for...Ch. 12 - For the reaction below, Kp = 1.16 at 800C....Ch. 12 - Many sugars undergo a process called mutarotation,...Ch. 12 - Peptide decomposition is one of the key processes...Ch. 12 - The creation of shells by mollusk species is a...Ch. 12 - Methanol, a common laboratory solvent, poses a...Ch. 12 - For the reaction: 3O2(g)2O3(g) K = 1.8 107 at a...Ch. 12 - An equilibrium mixture contains 0.60 g solid...Ch. 12 - At a particular temperature, 8.1 moles of NO2 gas...Ch. 12 - A sample of solid ammonium chloride was placed in...Ch. 12 - In a given experiment, 5.2 moles of pure NOCl was...Ch. 12 - For the reactionN2O4(g)2NO2(g),Kp=0.25 at a...Ch. 12 - Consider the following exothermic reaction at...Ch. 12 - For the following endothermic reaction at...Ch. 12 - A 1.604-g sample of methane (CH4) gas and 6.400 g...Ch. 12 - A 4.72-g sample of methanol (CH3OH) was placed in...Ch. 12 - At 35C, K = 1.6 105 for the reaction...Ch. 12 - Nitric oxide and bromine at initial partial...Ch. 12 - At 25C. Kp = 5.3 105 for the reaction...Ch. 12 - Consider the reaction P4(g)2P2(g) where Kp = 1.00 ...Ch. 12 - The partial pressures of an equilibrium mixture of...Ch. 12 - At 125C, KP = 0.25 for the reaction...Ch. 12 - A mixture of N2, H2, and NH3 is at equilibrium...Ch. 12 - Consider the decomposition equilibrium for...Ch. 12 - An 8.00-g sample of SO3 was placed in an evacuated...Ch. 12 - A sample of iron(II) sulfate was heated in an...Ch. 12 - At 5000 K and 1.000 atm, 83.00% of the oxygen...Ch. 12 - A sample of N2O4(g) is placed in an empty cylinder...Ch. 12 - A sample of gaseous nitrosyl bromide (NOBr) was...Ch. 12 - The equilibrium constant Kp for the reaction...Ch. 12 - For the reaction NH3(g)+H2S(g)NH4HS(s) K = 400. at...Ch. 12 - Given K = 3.50 at 45C for the reaction...Ch. 12 - In a solution with carbon tetrachloride as the...Ch. 12 - The hydrocarbon naphthalene was frequently used in...Ch. 12 - A gaseous material XY(g) dissociates to some...

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