Evaluate the double integral by first identifying it as the volume of a solid. 11. ∬ R ( 4 − 2 y ) d A , R = [ 0 , 1 ] × [ 0 , 1 ]
Evaluate the double integral by first identifying it as the volume of a solid. 11. ∬ R ( 4 − 2 y ) d A , R = [ 0 , 1 ] × [ 0 , 1 ]
Solution Summary: The author estimates the value of the given double integral over the rectangular region R. Since y is positive which lies between 0 to 1, it is enough to find the double
Evaluate the double integral by first identifying it as the volume of a solid.
11.
∬
R
(
4
−
2
y
)
d
A
,
R
=
[
0
,
1
]
×
[
0
,
1
]
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
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Area Between The Curve Problem No 1 - Applications Of Definite Integration - Diploma Maths II; Author: Ekeeda;https://www.youtube.com/watch?v=q3ZU0GnGaxA;License: Standard YouTube License, CC-BY