Concept explainers
The required amounts of components such as cement in sacks, sand and gravel in pounds, and water in gallons.
Answer to Problem 63AAP
The required amounts of components to produce
- Cement - 22.43 sacks
- Sand - 4126 lb
- Gravel - 8012 lb
- Water - 109 gal
Explanation of Solution
Write the formula for saturated surface dry density.
Calculate the saturated surface dry density of constituents using Equation (I) as shown in Table 1.
Constituents | Specific gravity | Density of water in | SSDD in |
Cement | 3.15 | 62.4 | 197 |
Sand | 2.65 | 62.4 | 165 |
Gravel | 2.65 | 62.4 | 165 |
Water | 1 | 62.4 | 62.4 |
Table 1
Write the formula for absolute volume of constituents per sack of cement.
Calculate the absolute volume of constituents per sack of cement using Equation (II) as shown in Table 2.
Constituent | Weight ratio of the constituents | Weight of cement per sack | Weight of the constituents | SSDD | Absolute volume of constituent in |
Cement | 1 | 94 | 94 | 197 | |
Sand | 1.9 | 94 | 178.6 | 165 | |
Gravel | 3.8 | 94 | 357.2 | 165 | |
Water | 5.5 gal per sack of cement | ||||
Total absolute volume of constituents per sack of cement |
Table 2
On dry basis:
The required amount of sacks of cement to produce
The required amount of sand to produce
The required amount of gravel to produce
The required amount of water to produce
On wet basis:
Since, the sand is having the moisture content of
The required amount of the wet sand is expressed as follows.
The weight of water present in the sand is expressed as follows.
The moisture content of the gravel is zero. Thus, the weight of water present in gravel is zero.
The required weight of water is expressed as follows.
Thus, the required amounts of components to produce
- Cement - 22.43 sacks
- Sand - 4126 lb
- Gravel - 8012 lb
- Water - 109 gal
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Chapter 12 Solutions
Foundations of Materials Science and Engineering
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