General, Organic, and Biological Chemistry - 4th edition
General, Organic, and Biological Chemistry - 4th edition
4th Edition
ISBN: 9781259883989
Author: by Janice Smith
Publisher: McGraw-Hill Education
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Textbook Question
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Chapter 12.2, Problem 12.3PP

Classify the carbon atoms in each compound as 1°, 2°, 3°, or 4°.

a. C H 3 C H 2 C H 2 C H 3

b. ( C H 3 ) 3 C H

Chapter 12.2, Problem 12.3PP, Classify the carbon atoms in each compound as 1°, 2°, 3°, or 4°. a. CH3CH2CH2CH3 b. (CH3)3CH

Expert Solution
Check Mark
Interpretation Introduction

(a)

Interpretation:

The carbon in the following compound should be classified as 1° , 2° , 3° or 4°.

  CH3CH2CH2CH3

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

In organic chemistry, carbons are classified as primary, secondary, tertiary and quaternary carbons.

Primary carbon ( 1° ) is defined as the carbon which is bonded to other carbon atom and it is present at the end of chain.

Secondary carbon ( 2° ) is defined as the carbon which is bonded to two other carbon atoms.

Tertiary carbon ( 3° ) is defined as the carbon which is bonded to other three carbon atoms.

Quaternary carbon ( 4° ) is defined as the carbon which is bonded to four other carbon atoms.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  1

Answer to Problem 12.3PP

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  2

Explanation of Solution

The given compound is CH3CH2CH2CH3.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  3

According to the above structure of compound, the terminal carbons present on both sides of the chain is classified as primary carbon as they are linked with one other carbon atom whereas carbon atoms which are present in between the terminal carbonsof the chain are linked with two other carbon atoms thus, classified as secondary carbon.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  4

Thus, two primary and two secondary carbons are present in the structure.

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation:

The carbon in the following compound should be classified as 1° , 2° , 3° or 4°.

  (CH3)3CH

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

In organic chemistry, carbons are classified as primary, secondary, tertiary and quaternary carbons.

Primary carbon ( 1° ) is defined as the carbon which is bonded to other carbon atom and it is present at the end of chain.

Secondary carbon ( 2° ) is defined as the carbon which is bonded to two other carbon atoms.

Tertiary carbon ( 3° ) is defined as the carbon which is bonded to other three carbon atoms.

Quaternary carbon ( 4° ) is defined as the carbon which is bonded to four other carbon atoms.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  5

Answer to Problem 12.3PP

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  6

Explanation of Solution

The given compound is (CH3)3CH.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  7

According to the above structure of compound, the terminal carbons (3 carbons) present is classified as primary carbon as they are linked with one other carbon atom whereas carbon atom which is present in the middle linked with three other carbon atoms thus, classified as tertiary carbon.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  8

Thus, three primary carbons and onetertiary carbon atom are present in the structure.

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation:

The carbon in the following compound should be classified as 1° , 2° , 3° or 4°.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  9

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

In organic chemistry, carbons are classified as primary, secondary, tertiary and quaternary carbons.

Primary carbon ( 1° ) is defined as the carbon which is bonded to other carbon atom and it is present at the end of chain.

Secondary carbon ( 2° ) is defined as the carbon which is bonded to two other carbon atoms.

Tertiary carbon ( 3° ) is defined as the carbon which is bonded to other three carbon atoms.

Quaternary carbon ( 4° ) is defined as the carbon which is bonded to four other carbon atoms.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  10

Answer to Problem 12.3PP

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  11

Explanation of Solution

The given compound is

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  12

According to the above structure of compound, the terminal carbons (3 carbons) present is classified as primary carbon as they are linked with one other carbon atom whereas the carbon which is linked with two other carbon atoms is classified as secondary carbon and the carbon which is linked with three other carbon atoms is classified as tertiary carbon.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  13

Thus, three primary carbons, one secondary carbon atom and one tertiary carbon atom are present in the structure.

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation:

The carbon in the following compound should be classified as 1° , 2° , 3° or 4°.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  14

Concept Introduction:

Compounds consist of carbon and hydrogen is known as hydrocarbons. Hydrocarbons are classified as saturated hydrocarbon and unsaturated hydrocarbon. Saturated hydrocarbons are those hydrocarbons in which carbon-carbon single bond is present as carbon is linked with four atoms. Unsaturated hydrocarbons are those hydrocarbons in which carbon-carbon multiple bonds are present that is double and triple bond.

In organic chemistry, carbons are classified as primary, secondary, tertiary and quaternary carbons.

Primary carbon ( 1° ) is defined as the carbon which is bonded to other carbon atom and it is present at the end of chain.

Secondary carbon ( 2° ) is defined as the carbon which is bonded to two other carbon atoms.

Tertiary carbon ( 3° ) is defined as the carbon which is bonded to other three carbon atoms.

Quaternary carbon ( 4° ) is defined as the carbon which is bonded to four other carbon atoms.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  15

Answer to Problem 12.3PP

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  16

Explanation of Solution

The given compound is

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  17

According to the above structure of compound, the terminal carbons (four carbons) present is classified as primary carbon as they are linked with one other carbon atom whereas the carbon which is linked with four other carbon atoms is classified as quaternary carbon.

General, Organic, and Biological Chemistry - 4th edition, Chapter 12.2, Problem 12.3PP , additional homework tip  18

Thus, four primary carbons and one quaternary carbon atom are present in the structure.

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Chapter 12 Solutions

General, Organic, and Biological Chemistry - 4th edition

Ch. 12.2 - Prob. 12.8PCh. 12.2 - Prob. 12.9PCh. 12.4 - Give the IUPAC name for each compound.Ch. 12.4 - Prob. 12.10PCh. 12.4 - Give the IUPAC name for each compound....Ch. 12.4 - Prob. 12.5PPCh. 12.4 - Prob. 12.6PPCh. 12.4 - Prob. 12.12PCh. 12.5 - Prob. 12.13PCh. 12.5 - Prob. 12.14PCh. 12.5 - Give the IUPAC name for each compound.Ch. 12.5 - Prob. 12.15PCh. 12.7 - Answer the following questions about pentane...Ch. 12.7 - Prob. 12.17PCh. 12.7 - Prob. 12.18PCh. 12.8 - Prob. 12.19PCh. 12.9 - Prob. 12.20PCh. 12.9 - Prob. 12.21PCh. 12.9 - Prob. 12.22PCh. 12 - Prob. 23PCh. 12 - Prob. 24PCh. 12 - The waxy coating on the surface of apple skins...Ch. 12 - Prob. 26PCh. 12 - Classify each carbon as 1°, 2°, 3°, or 4°. a....Ch. 12 - Give the structure of an alkane that fits each...Ch. 12 - Prob. 29PCh. 12 - Label each pair of compounds as constitutional...Ch. 12 - Consider compounds A, B, and C. Label each pair of...Ch. 12 - Consider compounds D,E, and F. Label each pair of...Ch. 12 - Prob. 33PCh. 12 - Consider compounds A-E and label each pair of...Ch. 12 - Draw structures that fit the following...Ch. 12 - Draw the five constitutional isomers having...Ch. 12 - Prob. 37PCh. 12 - Prob. 38PCh. 12 - Draw the five constitutional isomers that have...Ch. 12 - Pristane is a high molecular weight alkane found...Ch. 12 - Give the IUPAC name for each of the five...Ch. 12 - Give the IUPAC name for each of the five cyclic...Ch. 12 - Give the IUPAC name for each compoundCh. 12 - Give the IUPAC name for each compound.Ch. 12 - Give the IUPAC name for each compound. c....Ch. 12 - Give the IUPAC name for each compound.Ch. 12 - Give the IUPAC name for each cycloalkane.Ch. 12 - Give the IUPAC name for each ccycloalkane.Ch. 12 - Prob. 49PCh. 12 - Give the structure corresponding to each IUPAC...Ch. 12 - Each of the following IUPAC names is incorrect....Ch. 12 - Each of the following IUPAC names is incorrect....Ch. 12 - Draw three constitutional isomers having molecular...Ch. 12 - Draw four constitutional isomers having molecular...Ch. 12 - Draw a skeletal structure for each compound octane...Ch. 12 - Convert each compound to a skeletal structure CH3(...Ch. 12 - Convert each skeletal structure to a complete...Ch. 12 - Convert each skeletal structure to a complete...Ch. 12 - Which compound in each pair has the higher melting...Ch. 12 - Which compound in each pair has the higher boiling...Ch. 12 - Branching in an alkane chain decreases surface...Ch. 12 - Explain why the boiling points of heptane [CH3( CH...Ch. 12 - Explain why hexane is more soluble in...Ch. 12 - Mineral oil and Vaseline are both mixtures of...Ch. 12 - Write a balanced equation for the combustion of...Ch. 12 - Write a balanced equation for the combustion of...Ch. 12 - Write a balanced equation for the incomplete...Ch. 12 - Prob. 68PCh. 12 - Prob. 69PCh. 12 - Prob. 70PCh. 12 - Prob. 71PCh. 12 - Prob. 72PCh. 12 - Prob. 73PCh. 12 - Prob. 74PCh. 12 - Prob. 75PCh. 12 - Prob. 76PCh. 12 - Prob. 77PCh. 12 - Prob. 78PCh. 12 - Prob. 79PCh. 12 - A major component of animal fat is tristearin, (a)...Ch. 12 - Answer the following questions about the alkane...Ch. 12 - Prob. 82PCh. 12 - Answer the questions in Problem 12.81 for the...Ch. 12 - Prob. 84PCh. 12 - Prob. 85CPCh. 12 - Draw the structure of the 12 constitutional...Ch. 12 - Cyclopentane has a higher boiling point than...Ch. 12 - Prob. 88CP
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