   Chapter 12.2, Problem 5E ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042

#### Solutions

Chapter
Section ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042
Textbook Problem

# Evaluate the integrals in Problems 7-36. Check your results by differentiation. ∫ ( x 2 + 3 ) 3   2 x   d x

To determine

To calculate: The value of the integral (x2+3)32xdx.

Explanation

Given Information:

The provided integral is (x2+3)32xdx

Formula used:

The power formula of integrals:

undu=un+1n+1+C (forn1)

The power rule of differentiation:

ddu(un)=nun1

Calculation:

Consider the provided integral:

(x2+3)32xdx

Let u=x2+3, then derivative will be,

du=d(x2+3)=2xdx

Substitute du for 2xdx and u for x2+3 in provided integration.

(x2+3)32xdx=u3du

Now apply, the power formula of integrals:

undu<

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