   Chapter 12.2, Problem 6E ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042

#### Solutions

Chapter
Section ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042
Textbook Problem

# Evaluate the integrals in Problems 7-36. Check your results by differentiation. ∫ ( 3 x 3 + 1 ) 4 9 x 2   d x

To determine

To calculate: The value of the integral (3x3+1)49x2dx.

Explanation

Given Information:

The provided integral is (3x3+1)49x2dx

Formula used:

The power formula of integrals:

undu=un+1n+1+C (forn1)

The power rule of differentiation:

ddu(un)=nun1

Calculation:

Consider the provided integral:

(3x3+1)49x2dx

Let u=3x3+1, then derivative will be,

du=d(3x3+1)=9x2dx

Substitute du for 9x2dx and u for 3x3+1 in provided integration.

(3x3+1)49x2dx=u4du

Now apply, the power formula of integrals:

undu=

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