   Chapter 12.3, Problem 39E

Chapter
Section
Textbook Problem

# Projectile Motion In Exercises 41 and 42, use the model for projectile motion, assuming there is no air resistance and g = 9.8 meters per second per second.Determine the maximum height and range of a projectile tired at a height of 1.5 meters above tire ground with an initial speed of 100 meters per second and at an angle of 30 ∘ above the horizontal.

To determine
The maximum height and range of a projectile fired at a height of 1.5 meters above the ground with an initial speed of 100 meters per second and at an angle of 30° above the horizontal.

Explanation

Given:

The provided values are h=1.5,v0=100  and θ=30.

Explanation:

Using theorem r(t)=(v0cosθ)t.i^+[h+(v0sinθ)t0.5gt2]j^ with g=9.8 meters per second produces

r(t)=(100cos30)t.i^+[1.5+(100sin30)t4.9t2]j^=503t.i^+[1.5+50t4.9t2]j^

The velocity vector that is,

v(t)=503

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