   Chapter 12.5, Problem 36E ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042

#### Solutions

Chapter
Section ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042
Textbook Problem

# In Problems 29-36, find the particular solution to each differential equation. 36.   x e y   d x = ( x + 1 )   d y  when  x = 0 ,   y = 0

To determine

To calculate: The particular solution to the differential equation xeydx=(x+1)dy when x=0,y=0.

Explanation

Given Information:

The provided differential equation is xeydx=(x+1)dy and the values are x=0,y=0.

Formula used:

Solution of the differential equation g(y)dy=f(x)dx is g(y)dy=f(x)dx.

The logarithmic formula of integration is 1x+adx=ln|x+a|+C, where a is any real number.

The exponential formula of integration is exdx=ex+C.

Calculation:

Consider the differential equation, xeydx=(x+1)dy

Rearrange the equation as,

xx+1dx=eydy

Integrate both sides of the equation,

xx+1dx=eydy<

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