   Chapter 12.5, Problem 8E

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# 57095-12.5-8E-Question-Digital.docxProjectile Motion Repeat Exercise 7 for a baseball that is hit 4 feet above the ground at 80 feet per second and at an angle of 30° with respect to the ground.

(a)

To determine

To calculate: The vector valued function for the path of the baseball which is hit 4 feet above the ground at an inclination of 30° having speed 80 feet per second.

Explanation

Given:

A baseball is hit 4 feet above the ground at an inclination of 30°. The baseball has the speed of 80 feet per second.

Formula used:

The position vector of projectile motion, r(t)=(v0cosθ)ti+(h+(v0sinθ)t12gt2)j

Where h is the initial height of projectile, v0 is the initial speed of projectile and θ is the angle of elevation of projectile.

Calculation:

The given projectile motion is two-dimensional projectile motion. As it is provided that h,v0 and θ are initial height, velocity and inclination angle of projectile.

Apply the formula for the projectile motion. Let the position vector of baseball is r(t) and value of acceleration due to gravity is 32 feet per second.

r(t)=(v0cosθ)ti+(h+(v0sinθ)t

(b)

To determine

To calculate: The maximum height of the baseball which hit 4 feet above the ground at an inclination of 30° having speed 80 feet per second.

(c)

To determine

To calculate: The range of the baseball which hit 4 feet above the ground at an inclination of 30° having speed 80 feet per second.

(d)

To determine

To calculate: The arc length of the baseball trajectory which hit 4 feet above the ground at an inclination of 30° having speed 80 feet per second.

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