   Chapter 13, Problem 100SCQ

Chapter
Section
Textbook Problem

Which substance would have the greater influence on the vapor pressure of water when added to 1000. g of water: 10.0 g of sucrose (C12H22O11) or 10.0 g of ethylene glycol (HOCH2CH2OH)?

Interpretation Introduction

Interpretation: Among 10.0g of sucrose and 10.0g of ethylene glycol which has the greater influence on vapor pressure of 1000g water is to be identified.

Concept introduction:

Colligative properties: Properties of solutions which having influence on the concentration of the solute in it. Colligative properties are,

• Decrease in the vapor pressure
• Increase in the boiling point
• Decline in the boiling point
• Osmotic pressure

Raoult’s law: In a solution, vapor pressure of solvent is proportional to its mole fraction.

Psolvent=XsolventP0solvent

where,

P0solvent is the vapor pressure of pure solvent.

Molality (m): Molality is the number of moles of solute present in one kilogram of solvent.

Molality (m) =Numberofmolesofsolute1kgofsolvent

Explanation

Given,

Mass of sucrose is 10.0g

Mass of ethylene glycol is 10.0g

Mass of water is 1000.0g=1kg

Molar mass of sucrose is 342.30g/mol

Molar mass of ethylene glycol is 62.07g/mol

The number of moles of any substance can be determined using the equation

Numberofmole=GivenmassofthesubstanceMolarmass

Number of moles of sucrose is,

Numberofmole=10g342.30g/mol=0.029mol

Number of moles of sucrose is 0.029mol

Number of moles of ethylene glycol is,

Numberofmole=10g62.07g/mol=0

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts 