   Chapter 13, Problem 119AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# or each of the following sets of pressure/volume data, calculate the missing quantity. Assume that the temperature and the amount of gas remain constant.msp;  a . V =  123 L at 4 . 56 atm ; V =   ?  at 1 00 2 mm Hg b . V =  634 mL at 25 . 2 mm Hg ; V =  166 mL at  ? atm c . V =  443 L at 511 torr ; V =   ?  at l1 .0 5 kPa

Interpretation Introduction

(a)

Interpretation:

To calculate the missing quantity from the given pressure/volume data set.

Concept Introduction:

While calculating from the sets, the pressure, volume must have same units.

Explanation

The conversion factor for conversion of atm to mm Hg is

1 atm = 760 mm Hg

Now, to convert 4.56 atm to mm Hg we use dimensional analysis.

=4.56atm1×760 mm Hg1atm=3465.6 mm Hg

Thus, the pressure 4.56 atm = 3465.6 mm Hg.

According to Boyle’s law, the pressure of a gas is inversely proportional to the volume of the container

Interpretation Introduction

(b)

Interpretation:

To calculate the missing quantity from the given pressure/volume data set.

Concept Introduction:

While calculating from the sets, the pressure, volume must have same units.

Interpretation Introduction

(c)

Interpretation:

To calculate the missing quantity from the given pressure/volume data set.

Concept Introduction:

While calculating from the sets, the pressure, volume must have same units.

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 