Biology: The Unity and Diversity of Life (MindTap Course List)
Biology: The Unity and Diversity of Life (MindTap Course List)
14th Edition
ISBN: 9781305073951
Author: Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr
Publisher: Cengage Learning
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Textbook Question
Chapter 13, Problem 11GP

A single allele gives rise to the Hbs form of hemoglobin. Individuals who are homozygous for the allele (HbS/HbS) develop sickle-cell anemia (Section 9.6). Heterozygous individuals (HbA/HbS) have few symptoms. A couple who are both heterozygous for the HbS allele plan to have children. For each of the pregnancies, state the probability that they will have a child who is:

  • a. homozygous for the HbS allele
  • b. homozygous for the normal allele (HbA)
  • c. heterozygous: HbA/HbS
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Given that the normal hemoglobin allele (H) is dominant to the sickle-cell allele (h), each time two Hh individuals have a child together, what is the chance that the child will have sickle-cell disease? (a) 0% (b) 75% (c) 25% (d) 50% (e) 100%
The following is a summary of the possible sickle-cell genotypes and phenotypes: AA - cojmpletely normal AS - sickle-cell trait (this person has a combination of normal hemoglobin and the abnormal, sickled form of hemoglobin) SS - sickle-cell anemia (all abnormal hemoglobin)   Fill in the punnett square and answer the question: If both parents and heterozygous for sickle-cell disease, what are the possible genotypes and phenotypes for their children?
The following is a summary of the possible sickle-cell genotypes and phenotypes: AA - cojmpletely normal AS - sickle-cell trait (this person has a combination of normal hemoglobin and the abnormal, sickled form of hemoglobin) SS - sickle-cell anemia (all abnormal hemoglobin) Make a punnett square for help answering the question:  If both parents and heterozygous for sickle-cell disease, what are the possible genotypes and phenotypes for their children?
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  • Sickle cell anemia is caused by an individual carrying two recessive copies of the hemoglobin gene (hemoglobin gene is labeled Hb, and the recessive version is Hbs). Thus, to have sickle cell anemia, a person must have the genotype HbSHbS. A person that is HbAHbA carries two copies of the normal hemoglobin gene and does not have sickle cell anemia. A person that is heterozygous (HbAHbS) produces enough normal hemoglobin to not have sickle cell anemia but is also resistant to malaria. People that are heterozygous are called “carriers” because they carry the recessive allele but do not express the recessive phenotype. a. A couple are both resistant to malaria but do not have sickle cell anemia. Draw a Punnett square to represent this cross. b. What is the probability that the couple has three children where one child does not have a recessive allele, one child is resistant to malaria and does not have sickle cell anemia, and one child has sickle cell anemia?
    In a well-publicized paternity case, the following facts were determined: the mother, a beautiful, twice-convicted axe murderer, is blood type A. Her child, Lizzie, is type O and the alleged father, a mild-mannered felon convicted of check fraud, is type B. On the last day of the trial, another father – a missionary worker with blood type O is identified. Which of the two could be Lizzie’s father? Use the space below to support your conclusion.   I am really confused with the queshtion and need help finding the answer and how to prove can somone explain the answer and show it in a punnet sqaure please
    If a mother with sickle-cell anemia and a father with the sickle-cell trait havechildren, calculate the percentages of each genotype and phenotype of the offspring from the Punnett square.
  • A couple who are a carrier of sickle-cell disease with blood type A for the female and type B for the male (assume heterozygosity for blood types). What is the probability that they will have a son with blood type B and is sickle- cell? Please show the solution.
    Sickle cell anemia is a disease that is caused by a mutation in the gene that produces hemoglobin.  Hemoglobin carries oxygen in red blood cells.  The HbA allele produces normal hemoglobin and the HbS allele produces hemoglobin that sticks together and causes red blood cells to sickle.  Heterozygous individuals (HbAHbS) produce both normal and "sickle" hemoglobin so the HbA and HbS alleles are codominant.  Heterozygotes do not develop sickle cell anemia and are described as having the sickle cell trait.  Individuals that are homozygous for the sickle allele (HbSHbS) only produce "sickle" hemoglobin and develop sickle cell disease.A man who is homozygous for the normal allele married a woman with the sickle cell trait. What is the expected probability of this couple having a boy with the sickle cell trait? Record your answer as a value between 0 and 1 rounded to two decimal places.Answer
    Sickle cell anemia is a disease that is caused by a mutation in the gene that produces hemoglobin.  Hemoglobin carries oxygen in red blood cells.  The HbA allele produces normal hemoglobin and the HbS allele produces hemoglobin that sticks together and causes red blood cells to sickle.  Heterozygous individuals (HbAHbS) produce both normal and "sickle" hemoglobin so the HbA and HbS alleles are codominant.  Heterozygotes do not develop sickle cell anemia and are described as having the sickle cell trait.  Individuals that are homozygous for the sickle allele (HbSHbS) only produce "sickle" hemoglobin and develop sickle cell disease. A man with the sickle cell trait married a woman with the sickle cell trait. Determine the probability that they will have children with the sickle cell trait or sickle cell disease.Record your answer as a value between 0 and 1 rounded to two decimal places.  Answer
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