   Chapter 13, Problem 125AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
5 views

# or each of the following sets of volume/temperature data, calculate the missing quantity. Assume that the pressure and the amount of gas remain constant.msp;  a . V =  22 . 4 L at  0   ° C ; V =  44 . 4 L at  ? K b . V =  1 .0   ×  l 0 − 3 mL at -272  ° C ; V =   ?  at 25  ° C C . V =  32 . 3 L at -4 0   ° C ; V =  1 00.  L at  ? ° C

Interpretation Introduction

(a)

Interpretation:

To calculate the missing quantity from the given volume/temperature data set.

Concept Introduction:

While calculating from the sets, the temperature, volume must have same units.

Explanation

The conversion factor for conversion of degree centigrade to kelvin is

1 ° C = 273 K

Now, to convert 0 4.56 ° C to K, temperature = 0+273=273K

Thus, the temperature = 273 K.

According to Charles law, the volume of a gas is directly proportional to the temperature of the container. The equation we use according to this law is

V1T1=V2<

Interpretation Introduction

(b)

Interpretation:

To calculate the missing quantity from the given volume/temperature data set.

Concept Introduction:

While calculating from the sets, the temperature, volume must have same units.

Interpretation Introduction

(c)

Interpretation:

To calculate the missing quantity from the given volume/temperature data set.

Concept Introduction:

While calculating from the sets, the temperature, volume must have same units.

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