Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 13, Problem 13.13P
To determine
Find the depth of the excavation.
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A cut slope was excavated in saturated clays as shown in the figure. The soil has a unit weight of 17 kN/m³ and an undrained shear strength cᵤ = 20 kPa. The slope make an angle of 60° with the horizontal. Assume stability number m = 0.185. Slope failure occurs along the plane AC with BC = 8 m. Which of the following most nearly gives the maximum depth in meters up to which the cut could be made?
A vertical cut is made through a homogeneous soil mass (c=20 kPa,ϕ=20°,γ=16.50 ?? ?3 ⁄ ). Estimate thesafe depth of the cut, taking a factor of safety of 2 using Culmann’s method
Q.1. Refer to the infinite slope shown in Figure 1. Given: β = 19 ͦ,
ɣ = 20 kN/m3
, Ø = 33 ͦ,
and c’ = 47 kN/m2
. Find the height, H, such that a factor of safety, Fs = 3.1 is maintained
against sliding along the soil-rock interface.
Chapter 13 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Prob. 13.4PCh. 13 - Prob. 13.5PCh. 13 - Prob. 13.6PCh. 13 - Prob. 13.7PCh. 13 - Prob. 13.8PCh. 13 - Prob. 13.9PCh. 13 - Prob. 13.10P
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - Prob. 13.16PCh. 13 - Prob. 13.17PCh. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Prob. 13.20PCh. 13 - Prob. 13.21PCh. 13 - Prob. 13.22PCh. 13 - Prob. 13.23PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27CTPCh. 13 - Prob. 13.28CTPCh. 13 - Prob. 13.29CTP
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- A 9m cut slope is shown in the figure. The unit weight of soil is 17kN/m3. Friction angle and cohesion along the rock surface are 20 degrees and 24kPa respectively. The slope makes an angle of 300 from horizontal and the failure plane is at 150. Determine the developed frictional force on the failure plane.arrow_forwardConsider a slope given below with 10 slices, which has a circular failure surface. Each slice has 5 meters wide, and the weight of each slice was estimated on the basis of average height and a unit weight of soil ? = 16 kN/m3. The shear strength of the soil is assumed to be ? = 20 kPa and ? = 20°. The pertinent data for these ten slices is given in the table below. a) Determine the factor of safety using Janbu’s simplified method by assuming the initial ?? = ?. ?. b) Discuss how the factor of safety (stability of the Slope) will change due to the rainfall. You start to consider what environmental conditions will change first.arrow_forwardQ.3. A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 19 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?arrow_forward
- A vertical cut is made through a homogeneous soil mass (c=20kPa, φ=20deg, γ=16.5kN/m3). Using Culmann's method, determine the safe depth of the cut, taking a factor of safety of 2.0.arrow_forwardFigure 2 shows a slope with an inclination of : β = 58 ͦ. If AC represents a trial failure plane inclined at an angle θ = 32 ͦ with the horizontal, determine the factor of safety against sliding for the wedge ABC. Given: H = 6 m; ɣ = 19 kN/m3, Ø =21 ͦ, and c’= 38 kN/m2arrow_forwardA cut slope was excavated in a saturated clay. The slope made an angle of 39.55 degree with the horizontal. Slope failure occurred when the cut reached a depth of 6 m. Previous soil explorations showed that a rock layer was located at a depth of 10 m below the ground surface. Assuming an undrained condition and γsat = 18 kN/m3, Analyze the following. a. undrained cohesion of the clay.b. nature of the critical circle?c. With reference to the toe of the slope, at what distance did the surface of sliding intersect the bottom of the excavation?arrow_forward
- 1. A trapezoidal channel with a 5-m bottom width and side slope m = 1.0 discharges 35 m3/s. The slope is 0.004 and is paved with smooth concrete (n = 0.012). a. What is the critical depth? b. What is the normal depth? c. Is it a mild slope, or steep?Hint: Compare critical depth with normal depth OR find the critical slope (??) and compare it with bed slope(?0) d. Is the depth increasing or decreasing upstream? Why would that be (e.g. a spillway, dam, etc.)?Hint: For the first part, use ????=?0−?1−??2 to show if the depth is decreasing/increasing (either by finding Fr and S, OR by simply using the values of ?, ?? and ?0 to figure out if the fraction is +/-). e. How would you conceptualize the flow – what regime (e.g., S1, S2, S3, M1, M2, M3 in Figure 10.20)? f. Determine the depth 3.3 m upstream from a section that has a measured depth of 1.69 m.Hint: If you are using MATLAB, solve the GVF differential equation (????=?0−?1−??2) and find flow depth y at location x = -3.3 m. If you are…arrow_forwardA vertical cut is to be made in a purely cohesive clay deposit (c'=30kPa, φ'=0deg, γ=16kN/m3). Find the maximum height of the cut which can be temporarily supported. From the stability chart, the stability number can be used as 0.261.arrow_forward
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