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Chapter 13, Problem 13.15QP

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CHEMISTRY: ATOMS FIRST VOL 1 W/CON...

14th Edition
Burdge
ISBN: 9781259327933

Solutions

Chapter
Section
FindFindarrow_forward

CHEMISTRY: ATOMS FIRST VOL 1 W/CON...

14th Edition
Burdge
ISBN: 9781259327933
Interpretation Introduction

Interpretation: A solution has prepared at particular concentration at 20°C which is heated about 70°C . What will change along molarity, molality, percent by mass and mole fraction has to be explained.

Concept introduction

Molality (m): Molality is the number of moles of solute present in one kilogram of solvent.

Molality (m) =Numberofmolesofsolute1kgofsolvent

Molarity (M): Molarity is number of moles of the solute present in the one liter of the solution.

Molarity (M) =Numberofmolesofsolute1literofsolution

Molarity is estimation of moles in the total volume of the solution while molality is estimation of moles in relationship with solvent in the solution.

Mole fraction (X): Mole fraction is moles of each component is divided by total mass of the mixture.

Xsolute=molesofsolutemassofthesolution

Xsolvent=molesofsolventmassofthesolution

Percent by mass: Mass percent is mass of the element is divided by total mass of the compound and multiplied by 100.

Percent mass =Massoftheelementtotalmassofthecompound×100%

To explain change in molarity

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