# (a) Interpretation: The percent transmittance of the solution for the absorbance of 0.042 is to be calculated. Concept introduction: The percent transmittance of a solution is the ability of the solution to allow the monochromatic light to pass through it. The percent transmittance of a solution is the ratio of the intensity of monochromatic light incident on the solution to the intensity transmitted through the solution. The relation between the absorbance and transmittance is established by the Beer’s law. A = − log T

### Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

### Principles of Instrumental Analysis

7th Edition
Douglas A. Skoog + 2 others
Publisher: Cengage Learning
ISBN: 9781305577213

#### Solutions

Chapter 13, Problem 13.1QAP
Interpretation Introduction

Expert Solution

## Answer to Problem 13.1QAP

The percent transmittance for the absorbance of 0.042 is 90.8%.

### Explanation of Solution

The relation between the absorbance and transmittance is related by the Beer’s law.

The expression for the Beer’s law is:

A=logT

Where,

• A is the absorbance of the solution.
• T is the transmittance of the solution.

Rearrange the above expression in order to obtain the percent transmittance

10A=10(log(T%/100))

Simplify the expression for percent transmittance.

T%=(10A)100   ...... (1)

The value for A is 0.042.

Substitute the value in above equation.

T%=(10A)100T%=(10(0.042))100=(0.908)100=90.8%

The percent transmittance for the absorbance of 0.042 is 90.8%.

Interpretation Introduction

Expert Solution

## Answer to Problem 13.1QAP

The percent transmittance for the absorbance of 0.917 is 12.1%.

### Explanation of Solution

The relation between the absorbance and transmittance is related by the Beer’s law.

Write the expression for the Beer’s law.

A=logT

Where,

• A is the absorbance of the solution.
• T is the transmittance of the solution.

Rearrange the above expression in order to obtain the percent transmittance

10A=10(log(T%/100))

Simplify the expression for percent transmittance.

T%=(10A)100   ...... (1)

The value for A is 0.917.

Substitute 0.917 for A in equation (1).

T%=(10A)100T%=(10(0.917))100=(0.121)100=12.1%

The percent transmittance for the absorbance of 0.917 is 12.1%.

Interpretation Introduction

Expert Solution

## Answer to Problem 13.1QAP

The percent transmittance for the absorbance of 0.245 is 56.9%.

### Explanation of Solution

The relation between the absorbance and transmittance is related by the Beer’s law.

The expression for the Beer’s law is:

A=logT

Where,

• A is the absorbance of the solution.
• T is the transmittance of the solution.

Rearrange the above expression in order to obtain the percent transmittance

10A=10(log(T%/100))

Simplify the expression for percent transmittance.

T%=(10A)100   ...... (1)

The value for A is 0.245.

Substitute 0.245 for A in equation (1).

T%=(10(0.245))100=(0.569)100=56.9%

The percent transmittance for the absorbance of 0.245 is 56.9%.

Interpretation Introduction

Expert Solution

## Answer to Problem 13.1QAP

The percent transmittance for the absorbance of 0.379 is 41.8%.

### Explanation of Solution

The relation between the absorbance and transmittance is related by the Beer’s law.

The expression for the Beer’s law is:

A=logT

Where,

• A is the absorbance of the solution.
• T is the transmittance of the solution.

Rearrange the above expression in order to obtain the percent transmittance

10A=10(log(T%/100))

Simplify the expression for percent transmittance.

T%=(10A)100   ......(1)

The value for A is 0.379.

Substitute 0.379 for A in equation (1).

T%=(10(0.379))100=(0.418)100=41.8%

The percent transmittance for the absorbance of 0.379 is 41.8%.

Interpretation Introduction

Expert Solution

## Answer to Problem 13.1QAP

The percent transmittance for the absorbance of 0.435 is 36.7%.

### Explanation of Solution

The relation between the absorbance and transmittance is related by the Beer’s law.

The expression for the Beer’s law is:

A=logT

Where,

• A is the absorbance of the solution.
• T is the transmittance of the solution.

Rearrange the above expression in order to obtain the percent transmittance

10A=10(log(T%/100))

Simplify the expression for percent transmittance.

T%=(10A)100   ......(1)

The value for A is 0.379.

Substitute 0.435 for A in equation (1).

T%=(10(0.435))100=(0.367)100=36.7%

The percent transmittance for the absorbance of 0.435 is 36.7%.

Interpretation Introduction

Expert Solution

## Answer to Problem 13.1QAP

The percent transmittance for the absorbance of 0.513 is 30.7%.

### Explanation of Solution

The relation between the absorbance and transmittance is related by the Beer’s law.

The expression for the Beer’s law is:

A=logT

Where,

• A is the absorbance of the solution.
• T is the transmittance of the solution.

Rearrange the above expression in order to obtain the percent transmittance

10A=10(log(T%/100))

Simplify the expression for percent transmittance.

T%=(10A)100   ......(1)

The value for A is 0.513.

Substitute 0.513 for A in equation (1).

T%=(10(0.513))100=(0.307)100=30.7%

The percent transmittance for the absorbance of 0.513 is 30.7%.

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