 # The isomerization of cyclopropane, C 3 H 6 , is believed to occur by the mechanism shown in the following equations: C 3 H 6 + C 3 H 5 → k 1 C 3 H 6 + C 3 H 6 * ( Step 1 ) C 3 H 6 * → k 2 C 2 ​ = ​ CHCH 3 ( Step 2 ) Here C 3 H 6 * is an excited cyclopropane molecule. At low pressure, Step 1 is much slower than Step 2. Derive the rate law for this mechanism at low pressure. Explain. ### General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343 ### General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
Publisher: Cengage Learning
ISBN: 9781305580343

#### Solutions

Chapter
Section
Chapter 13, Problem 13.89QP
Textbook Problem
273 views

## The isomerization of cyclopropane, C3H6, is believed to occur by the mechanism shown in the following equations: C 3 H 6 + C 3 H 5 → k 1 C 3 H 6 + C 3 H 6 * ( Step   1 ) C 3 H 6 * → k 2 C 2 ​ = ​ CHCH 3 ( Step   2 ) Here C 3 H 6 * is an excited cyclopropane molecule. At low pressure, Step 1 is much slower than Step 2. Derive the rate law for this mechanism at low pressure. Explain.

Expert Solution
Interpretation Introduction

Interpretation:

The rate law for the isomerization of Cyclopropane has to be derived and explained.

Concept Introduction:

The rate of reaction is the quantity of formation of product or the quantity of reactant used per unit time. The rate of reaction doesn’t depend on the sum of amount of reaction mixture used.

The raise in molar concentration of product of a reaction per unit time or decrease in molarity of reactant per unit time is called rate of reaction and is expressed in units of mol/(L.s) .

The equation that relates the reaction rate to the reactants concentrations that is raised to various powers is called as rate law.

Rate law can be determined by the slow step or otherwise called as rate-determining step.

Rate constant is defined as proportionality constant in the connection between rate and concentrations.

To derive and explain the rate law for the mechanism

### Explanation of Solution

The equation for the isomerization of Cyclopropane is

C3H6+C3H6k1C3H6+C3H6*(Step1) </

### Want to see the full answer?

Check out a sample textbook solution.See solution

### Want to see this answer and more?

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

See solution 