Chapter 13, Problem 1CQ

To determine

The quantity with the greater density among $1\text{g}$ of mercury and $1000\text{g}$ of water.

Answer to Problem 1CQ

$1\text{g}$ of mercury has greater density than $1000\text{g}$ of water.

Explanation of Solution

Write the expression to calculate the density of the object.

    $\rho =\frac{m}{V}$        (I)

Here, $V$ is the volume, $m$ is the mass of the object and $\rho$ is the density.

Density is defined as the mass per unit volume and is independent of the size of the object.

The density of water is, ${\rho }_{\text{w}}=1\text{g}/{\text{cm}}^{\text{3}}$.

The density of mercury is, ${\rho }_{\text{M}}=13.6\text{g}/{\text{cm}}^{\text{3}}$.

It is clear that,

    $\begin{array}{c}{\rho }_{\text{M}}>{\rho }_{\text{w}}\\ 13.6\text{g}/{\text{cm}}^{\text{3}}>1\text{g}/{\text{cm}}^{\text{3}}\end{array}$

The density of mercury is greater than the density of water.

Therefore, $1\text{g}$ of mercury has greater density than $1000\text{g}$ of water.