An Introduction to Physical Science
An Introduction to Physical Science
14th Edition
ISBN: 9781305079137
Author: James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher: Cengage Learning
Question
Chapter 13, Problem 1E

(a)

To determine

Balance the given chemical equation: CuCl2+H2Cu+HCl

(a)

Expert Solution
Check Mark

Answer to Problem 1E

The balanced chemical equation is written as,

CuCl2+H2Cu+2HCl

Explanation of Solution

Given info: The chemical equation is given as,

CuCl2+H2Cu+HCl

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

CuCl2+H2Cu+HCl

In the above reaction, there are two chlorine atoms and two hydrogen atoms in the reactant side and there is one chlorine atom and one hydrogen atom on the product side. Therefore, multiply HCl with 2 on the product side. The balanced chemical equation is written as,

CuCl2+H2Cu+2HCl

Conclusion:

Therefore, the balanced chemical equation is written as,

CuCl2+H2Cu+2HCl

(b)

To determine

Balance the given chemical equation: Fe+O2Fe2O3

(b)

Expert Solution
Check Mark

Answer to Problem 1E

The balanced chemical equation is written as,

4Fe+3O22Fe2O3

Explanation of Solution

Given info: The chemical equation is given as,

Fe+O2Fe2O3

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

Fe+O2Fe2O3

In the above reaction, there is one iron atom and two oxygen atoms in the reactant side and there are two iron atoms and three oxygen atoms on the product side. If iron on the reactant side is multiplied by 2 then O2 must be multiplied by 32 to balance the chemical equation. But in the balanced equation coefficients should be a whole number not a fraction.

Therefore, multiply Fe with 4 and O2 with 3 on the reactant side. Multiply Fe2O3 with 2 . The balanced chemical equation is written as,

4Fe+3O22Fe2O3

Conclusion:

Therefore, the balanced chemical equation is written as,

4Fe+3O22Fe2O3

(c)

To determine

Balance the given chemical equation: Al+H2SO4Al2(SO4)3+H2

(c)

Expert Solution
Check Mark

Answer to Problem 1E

The balanced chemical equation is written as,

2Al+3H2SO4Al2(SO4)3+3H2

Explanation of Solution

Given info: The chemical equation is given as,

Al+H2SO4Al2(SO4)3+H2

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

Al+H2SO4Al2(SO4)3+H2

In the above reaction, there is one Al atom on the reactant side and there are two Al atoms on the product side. Therefore multiply Al atom with 2 on the reactant side. The chemical equation after balancing aluminium atom is written as,

2Al+H2SO4Al2(SO4)3+H2

In the above reaction, there is one SO4 unit in H2SO4 and there are three SO4 units in Al2(SO4)3 . Therefore, multiply H2SO4 with 3 . The chemical equation after balancing SO4 unit is written as,

2Al+3H2SO4Al2(SO4)3+H2

In the above reaction, there are six hydrogen atoms on the reactant side and there are two hydrogen atoms on product side. Therefore, multiply H2 with 3 . The balanced chemical equation is written as,

2Al+3H2SO4Al2(SO4)3+3H2

Conclusion:

Therefore, the balanced chemical equation is written as,

2Al+3H2SO4Al2(SO4)3+3H2

(d)

To determine

Balance the given chemical equation: CaC2+H2OCa(OH)2+C2H2

(d)

Expert Solution
Check Mark

Answer to Problem 1E

The balanced chemical equation is written as,

CaC2+2H2OCa(OH)2+C2H2

Explanation of Solution

Given info: The chemical equation is given as,

CaC2+H2OCa(OH)2+C2H2

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

CaC2+H2OCa(OH)2+C2H2

In the above reaction, there are two hydrogen atoms and one oxygen atom on the reactant side and there are four hydrogen atoms and two oxygen atoms on the product side. Therefore, multiply H2O with 2 on the reactant side. The balanced chemical equation is written as,

CaC2+2H2OCa(OH)2+C2H2

Conclusion:

Therefore, the balanced chemical equation is written as,

CaC2+2H2OCa(OH)2+C2H2

(e)

To determine

Balance the given chemical equation: KNO3KNO2+O2

(e)

Expert Solution
Check Mark

Answer to Problem 1E

The balanced chemical equation is written as,

2KNO32KNO2+O2

Explanation of Solution

Given info: The chemical equation is given as,

KNO3KNO2+O2

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

KNO3KNO2+O2

In the above reaction, there are three oxygen atoms on the reactant side and there are four oxygen atoms on the product side. If O2 is multiplied by 12 then the above equation will be balanced. But the coefficient in the balanced equation should be a whole number not a fraction.

Therefore, multiply KNO3 with 2 and KNO2 with 2 . The balanced chemical equation is written as,

2KNO32KNO2+O2

Conclusion:

Therefore, the balanced chemical equation is written as,

2KNO32KNO2+O2

(f)

To determine

Balance the given chemical equation: C6H6+O2CO2+H2O

(f)

Expert Solution
Check Mark

Answer to Problem 1E

The balanced chemical equation is written as,

2C6H6+15O212CO2+6H2O

Explanation of Solution

Given info: The chemical equation is given as,

C6H6+O2CO2+H2O

Explanation:

In the balanced chemical equation, the number of same atom in the product and reactant side should be equal.

The given chemical equation is written as,

C6H6+O2CO2+H2O

In the above reaction, there are six carbon atoms on the reactant side and one carbon atom on the product side. Therefore multiply CO2 with 6 . The chemical equation is written as,

C6H6+O26CO2+H2O

In the above reaction, there are six hydrogen atoms on the reactant side and two hydrogen atoms on the product side. Therefore multiply H2O with 3 . The chemical equation is written as,

C6H6+O26CO2+3H2O

In the above reaction, there are two oxygen atoms on the reactant side and fifteen oxygen atoms on the product side. Therefore, multiply O2 with 152 . The chemical equation is written as,

C6H6+152O26CO2+3H2O

In the balanced equation, the coefficients should be a whole number not a fraction. Therefore, multiply the above equation with 2 . The balanced chemical equation is written as,

2C6H6+15O212CO2+6H2O

Conclusion:

Therefore, the balanced chemical equation is written as,

2C6H6+15O212CO2+6H2O

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Chapter 13 Solutions

An Introduction to Physical Science

Ch. 13.3 - Prob. 13.5CECh. 13.4 - What is oxidation?Ch. 13.4 - Prob. 2PQCh. 13.4 - Prob. 13.6CECh. 13.5 - Prob. 1PQCh. 13.5 - Prob. 2PQCh. 13.5 - How many grams are in 1.70 moles of potassium...Ch. 13.5 - What is the molarity of a salt (NaCl) solution in...Ch. 13 - Prob. AMCh. 13 - Prob. BMCh. 13 - Prob. CMCh. 13 - Prob. DMCh. 13 - Prob. EMCh. 13 - Prob. FMCh. 13 - Prob. GMCh. 13 - Prob. HMCh. 13 - Prob. IMCh. 13 - Prob. JMCh. 13 - Prob. KMCh. 13 - Prob. LMCh. 13 - Prob. MMCh. 13 - Prob. NMCh. 13 - Prob. OMCh. 13 - Prob. PMCh. 13 - Prob. QMCh. 13 - Prob. RMCh. 13 - Prob. SMCh. 13 - Prob. TMCh. 13 - Prob. UMCh. 13 - Prob. VMCh. 13 - Prob. WMCh. 13 - Prob. XMCh. 13 - Prob. YMCh. 13 - Prob. ZMCh. 13 - When iron rusts in the presence of oxygen and...Ch. 13 - How many hydrogen atoms are indicated by 2...Ch. 13 - Prob. 3MCCh. 13 - Prob. 4MCCh. 13 - Consider the complete combustion of octane, C8H18....Ch. 13 - Prob. 6MCCh. 13 - Prob. 7MCCh. 13 - What is the pH of a solution ten times as acidic...Ch. 13 - Prob. 9MCCh. 13 - Prob. 10MCCh. 13 - One mole of hydrogen peroxide, H2O2, would consist...Ch. 13 - One mole of hydrogen peroxide, H2O2, would consist...Ch. 13 - Prob. 1FIBCh. 13 - Prob. 2FIBCh. 13 - Prob. 3FIBCh. 13 - Prob. 4FIBCh. 13 - Prob. 5FIBCh. 13 - Prob. 6FIBCh. 13 - Prob. 7FIBCh. 13 - Prob. 8FIBCh. 13 - Prob. 9FIBCh. 13 - Prob. 10FIBCh. 13 - Prob. 11FIBCh. 13 - Prob. 12FIBCh. 13 - Prob. 13FIBCh. 13 - Prob. 14FIBCh. 13 - Prob. 1SACh. 13 - Iodine is (a) blue-black, (b) crystalline, and (c)...Ch. 13 - Prob. 3SACh. 13 - Prob. 4SACh. 13 - Prob. 5SACh. 13 - Prob. 6SACh. 13 - Prob. 7SACh. 13 - Prob. 8SACh. 13 - Prob. 9SACh. 13 - Prob. 10SACh. 13 - Why does a reaction vessel feel warm during an...Ch. 13 - What is absorbed during bond breaking but...Ch. 13 - Prob. 13SACh. 13 - Prob. 14SACh. 13 - Prob. 15SACh. 13 - Prob. 16SACh. 13 - Prob. 17SACh. 13 - Prob. 18SACh. 13 - Prob. 19SACh. 13 - Prob. 20SACh. 13 - What is the pH of a neutral aqueous solution? How...Ch. 13 - What color will litmus be in a solution of pH 9? A...Ch. 13 - Prob. 23SACh. 13 - Prob. 24SACh. 13 - Prob. 25SACh. 13 - Prob. 26SACh. 13 - The reaction of an acid with a hydroxide base...Ch. 13 - Prob. 28SACh. 13 - Prob. 29SACh. 13 - Prob. 30SACh. 13 - Prob. 31SACh. 13 - Prob. 32SACh. 13 - Prob. 33SACh. 13 - Prob. 34SACh. 13 - Prob. 35SACh. 13 - Prob. 36SACh. 13 - Prob. 37SACh. 13 - Suppose you are given the volume (in liters) of a...Ch. 13 - Prob. 1VCCh. 13 - Prob. 1AYKCh. 13 - Prob. 2AYKCh. 13 - Explain why a bag of charcoal briquettes contains...Ch. 13 - An Alka-Seltzer tablet contains solid citric acid...Ch. 13 - The human body converts sugar into carbon dioxide...Ch. 13 - Prob. 6AYKCh. 13 - Prob. 7AYKCh. 13 - Prob. 8AYKCh. 13 - Prob. 9AYKCh. 13 - Prob. 10AYKCh. 13 - Prob. 1ECh. 13 - Balance these chemical equations. (a) SO2+O2SO3...Ch. 13 - Prob. 3ECh. 13 - Prob. 4ECh. 13 - Prob. 5ECh. 13 - Prob. 6ECh. 13 - Prob. 7ECh. 13 - Prob. 8ECh. 13 - Prob. 9ECh. 13 - Prob. 10ECh. 13 - Prob. 11ECh. 13 - Prob. 12ECh. 13 - Prob. 13ECh. 13 - Prob. 14ECh. 13 - Prob. 15ECh. 13 - Prob. 16ECh. 13 - Two moles of hydrogen sulfide, H2S, would consist...Ch. 13 - Four moles of sulfur dioxide, SO2, would consist...Ch. 13 - Prob. 19ECh. 13 - Prob. 20ECh. 13 - Prob. 21ECh. 13 - How many moles are in 15.0 g of copper sulfate...Ch. 13 - Prob. 23ECh. 13 - How many molecules are in 2.49 103 g of CuSO4?Ch. 13 - Prob. 25ECh. 13 - Prob. 26ECh. 13 - Prob. 27ECh. 13 - Prob. 28E
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