   Chapter 13, Problem 30PS

Chapter
Section
Textbook Problem

What is the boiling point of a solution composed of 15.0 g of urea, (NH2)2CO, in 0.500 kg of water?

Interpretation Introduction

Interpretation: The Boiling point of solution (Water) to be identified.

Concept introduction:

Boiling point elevation: The boiling point of the solution varies with the solute concentration.

Elevation in boiling point = ΔTbp= Kbp. msolute,where,Kbpismolal boiling point elevation constant,msoluteis molality of solute

Explanation

Given data:

Massofurea(solute) =15gMass of Water = 0.500 kg Boilingpointofsolution= ?

No.ofmoles=massmolarmass

Mole of solute = 15g60.06g/mol=0.249 mol

Known data:

Boiling point of water = 100oCKbpofWater=+0.5121oC/m

Calculation of the molality of solute  in solution(m):_molality = Moles of solute (mol)Amount of solvent(in kg) = (0.249 mol)0.500 kg= 0.498m

Boiling point elevation:_Elevation in boiling point = ΔTbp= Kbp

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