   Chapter 13, Problem 35PS

Chapter
Section
Textbook Problem

You dissolve 15.0 g of sucrose, C12H22O11, in a cup of water (225 g). What is the freezing point of the solution?

Interpretation Introduction

Interpretation: The freezing point of solution has to be identified.

Concept introduction:

Freezing point elevation: The freezing point of the solution varies with the solute concentration.

Depression in Freezing point = ΔTfp= Kfp. msolute,where,Kfpismolal boiling point elevation constant,msoluteis molality of solute

Explanation

Given data:

Massofsucrose(solute) =15gMass of Water = 0.225 kg Freezingpointofsolution= ?

Numberofmole=MassofthesubstanceingramMolarmass

Mole of solute = 15g342.3g/mol=0.044mol

Freezing point of water = 0oCKfpofWater=-1.86oC/m

Calculate the molality of solute  in solution(m):_molality = Moles of solute (mol)Amount of solvent(in kg) = (0.044 mol)0

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