BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Solutions

Chapter
Section
BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

Fill in the blanks in the table. Aqueous solutions are assumed.

images

Interpretation Introduction

Interpretation: The mole fraction, molality, and weight percent of given compounds has to be identified.

Concept introduction:

Mole fraction: Amount of that component divided by the total amount of all of the components of the mixture ( nA +  nB +  n...).

Mole fraction of A (χA)= nA nA +  nB +  n...

Molality: The amount of solute (mol) per kilogram of solvent.

Concentration (C, mol/kg) =  molality of solute = Amount of solute (mol)Mass of solvent (Kg)

Weight percent: The mass of one component divided by the total mass of the mixture, multiplied by 100%

weight % A = Mass of A Mass of A + Mass of B + Mass of C + ...×100%

Explanation
  • Calculate mole fraction of NaI:

Given data:

Molality = 0.15 mol/ kg

 0.15 moles of NaI is in 1Kg of water.

No.ofmoles=massmolarmass

Mass of NaI = (moles of NaI) (molar mass of NaI)=(0.15 mol)(149.89g/mol)=22.48g

Mass of water = 1000 g.Moles of water=massmolarmass=1000g18g/mol=55.55moles

Mole fraction of A (χA)= nA nA +  nB +  n...

nNaI= 0.15 molnWater= 55.55 molMole fraction : (χNaI) = nNaI nNaI +  nWater  = 0.15mol0.15 mol + 55.55 mol = 0.0027=2.7×103

Convert the mass of water into unit of moles and substitute in the respective mole fraction equation as shown above. Hence, the mole fraction of NaI is 2.7×103

  • Calculate weight percent of NaI:

    Known data:

    Mass of NaI = 22.48gMass of water = 1000 g.

    weight % A = Mass of A Mass of A + Mass of B + Mass of C + ...×100%

    weight % NaI = Mass of NaI Mass of NaI + Mass of water ×100%22.48 g(22.48 g)+(1000 g)×100% = 2.3%

The weight percent of NaI is calculated as shown above. Hence, the weight percent obtained is 2.3%

  • Calculate molality of Ethanol:

    Given data:

    Weight percent = 5.0

    Weight percent = 5.0  indictaes 5g of ethanol in100g of solution.Mass of Water (solvent) = mass of solution - mass of ethanol = 100 g - 5 g = 95 g

    No.ofmoles=massmolarmass

    no.of moles (ethanol) = 5 g 46.07 g/mol = 0.1085 mol

    Amount of solvent = 0.095 Kg

    Molality of a solute is defined as the amount of solute dissolves in kilogram of solvent.

    Molality=molesofsoluteMassofsolventinkg

    No.ofmoles (mol)Mass of solvent (Kg)0.1085 mol0.095 kg = 1.14 mol/Kg = 1

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Chapter 13 Solutions

Show all chapter solutions add

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

When added sugar is consumed in excess of calorie need, it alters blood lipids in potentially harmful ways. it ...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

How do eating disorders affect health?

Understanding Nutrition (MindTap Course List)

How does a tendon differ from a ligament?

Human Biology (MindTap Course List)

What is population genetics?

Human Heredity: Principles and Issues (MindTap Course List)