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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

The dispersed phase of a certain colloidal dispersion consists of spheres of diameter 1.0 × 102 nm.

  1. (a) What are the volume ( V = 4 3 π r 2 ) and surface area (A = πr2) of each sphere?
  2. (b) How many spheres are required to give a total volume of 1.0 cm3? What is the total surface area of these spheres in square meters?

(a)

Interpretation Introduction

Interpretation: The volume and surface area of each sphere of diameter 1×102nm has to be determined.

Concept introduction:

Colloids: It is a homogeneous particle where one of the substances is dispersed throughout the other substance.

Volume of a sphere is calculated by the equation,

  V=43πr3

Surface area of a sphere is calculated by the equation,

  V=4πr2

Explanation

Given,

Diameter=1.0×102nm=1.0×107mRadius=1.0×107m2=5×108m

Volume of each sphere is calculated,

V=43πr3=43(3.14)(5×108m)3=5

(b)

Interpretation Introduction

Interpretation: The number of spheres and the total surface area has to be calculated.

Concept introduction:

Colloids: It is a homogeneous particle where one of the substances is dispersed throughout the other substance.

Volume of a sphere is calculated by the equation,

  V=43πr3

Surface area of a sphere is calculated by the equation,

  V=4πr2

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