BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
10th Edition
ISBN: 9781305967359
Author: STARR
Publisher: CENGAGE L
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Chapter 13, Problem 5GP
A single allele gives rise to the HbS form of hemoglobin. Individuals who are homozygous for the allele (HbS/HbS) develop sickle-cell anemia (Section 9.5). Heterozygous individuals (HbA/ HbS) have few Symptoms. A couple who are both heterozygous for the HbS allele plan to have children. For each of the pregnancies, determine the probability that their child will be:
| a. homozygous for the HbS allele |
| b. homozygous for the normal allele (HbA) |
| c. heterozygous: HbA/HbS |
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Chapter 13 Solutions
BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
Ch. 13 - A heterozygous individual has _______ for a trait...Ch. 13 - An organisms observable traits constitute its...Ch. 13 - In genetics, F stands for filial, which means...Ch. 13 - The offspring of the cross AAaa are ________. a....Ch. 13 - The second-generation offspring of a cross between...Ch. 13 - Refer to question 4. Assuming complete dominance,...Ch. 13 - Independent assortment means _______. a. alleles...Ch. 13 - A testcross is a way to determine _________. a....Ch. 13 - Assuming complete dominance, crosses between two...Ch. 13 - The probability of a crossover occurring between...
Ch. 13 - True or false? All traits are inherited in a...Ch. 13 - One gene that affects three traits is an example...Ch. 13 - ________ in a trait is indicated by a bell curve.Ch. 13 - The phenotype of individuals heterozygous for...Ch. 13 - Match the terms with the best description. ___...Ch. 13 - Mendel crossed a true-breeding pea plant with...Ch. 13 - Assuming that independent assortment occurs during...Ch. 13 - Determine the predicted genotype frequencies among...Ch. 13 - Prob. 4GPCh. 13 - A single allele gives rise to the HbS form of...Ch. 13 - In sweet pea plant, an allele for purple flowers...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
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- Sickle cell anemia is caused by an individual carrying two recessive copies of the hemoglobin gene (hemoglobin gene is labeled Hb, and the recessive version is Hbs). Thus, to have sickle cell anemia, a person must have the genotype HbSHbS. A person that is HbAHbA carries two copies of the normal hemoglobin gene and does not have sickle cell anemia. A person that is heterozygous (HbAHbS) produces enough normal hemoglobin to not have sickle cell anemia but is also resistant to malaria. People that are heterozygous are called “carriers” because they carry the recessive allele but do not express the recessive phenotype. a. A couple are both resistant to malaria but do not have sickle cell anemia. Draw a Punnett square to represent this cross. b. What is the probability that the couple has three children where one child does not have a recessive allele, one child is resistant to malaria and does not have sickle cell anemia, and one child has sickle cell anemia?arrow_forwardThe following is a summary of the possible sickle-cell genotypes and phenotypes: AA - cojmpletely normal AS - sickle-cell trait (this person has a combination of normal hemoglobin and the abnormal, sickled form of hemoglobin) SS - sickle-cell anemia (all abnormal hemoglobin) Make a punnett square for help answering the question: If both parents and heterozygous for sickle-cell disease, what are the possible genotypes and phenotypes for their children?arrow_forwardJan and Michael are both carriers for the cystic fibrosis allele. If Jan and Michael have five children, what the probability that three or more of the children will have the disease?arrow_forward
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