   Chapter 13, Problem 60GQ

Chapter
Section
Textbook Problem

If you dissolve 2.00 g of Ca(NO3)2 in 750 g of water, what is the molality of Ca(NO3)2? What the total molality of ions in solution? (Assume total dissociation of the ionic solid.)

Interpretation Introduction

Interpretation: Molality of Ca(NO3)2 and the total molality of the ions in the solution are to be determined.

Concept introduction:

Mole fraction: Amount of that component divided by the total amount of all of the components of the mixture ( nA +  nB +  n...).

Mole fraction of A (χA)= nA nA +  nB +  n...

Weight percent: The mass of one component divided by the total mass of the mixture, multiplied by 100%

weight % A = Mass of A Mass of A + Mass of B + Mass of C + ...×100%

The number of moles of any substance can be determined using the equation

Numberofmole=GivenmassofthesubstanceMolarmass

Molality (m): Molality is the number of moles of solute present in one kilogram of solvent.

Molality (m) =Numberofmolesofsolute1kgofsolvent

Molarity (M): Molarity is number of moles of the solute present in the one liter of the solution.

Molarity (M) =Numberofmolesofsolute1literofsolution

Density is calculated by the equation,

Density=massvolume

Explanation

Molality of Ca(NO3)2 and the total molality of the ions in the solution is calculated

Given,

Mass of Ca(NO3)2 is 2.00g

Mass of water is 750g=0.750kg

Molar mass of Ca(NO3)2 is 164.09g/mol

The number of moles of any substance can be determined using the equation

Numberofmole=GivenmassofthesubstanceMolarmass=2.00g164.09g/mol=0

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