   Chapter 13, Problem 63QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# What will the volume of the sample become if 459 mL of an ideal gas at 27  ° C and 1 .0 5 atm is cooled to 15  ° C and 0. 997 atm?

Interpretation Introduction

Interpretation:

The volume of the sample should be calculated if an ideal gas is cooled.

Concept Introduction:

According to ideal gas equation:

PV=nRT

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature.

The value of Universal gas constant can be taken as 0.082 L atm K1 mol1.

Explanation

Calculation:

The ideal gas equation for first case (before cooling) is as follows:

P1V1=nRT1...... (1)

Number of moles and Universal gas constant is same for both cases thus; ideal gas equation for second case (after cooling) is as follows:

P2V2=nRT2...... (2)

On comparing two equations:

P1V1T1=P2V2T2

On rearranging,

V2=P1V1T2T1P2

Convert the temperature from K to C as follows:

0 C=273.15 K

Thus,

27 C=(27+273

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