   Chapter 13, Problem 74GQ

Chapter
Section
Textbook Problem

Water at 25 °C has a density of 0.997 g/cm3. Calculate the molality and molarity of pure water at this temperature.

Interpretation Introduction

Interpretation: Molality and molarity of pure water has to be calculated under given conditions.

Concept introduction:

The number of moles of any substance can be determined using the equation

Numberofmole=GivenmassofthesubstanceMolarmass

Molality (m): Molality is the number of moles of solute present in one kilogram of solvent.

Molality (m) =Numberofmolesofsolute1kgofsolvent

Molarity (M): Molarity is number of moles of the solute present in the one liter of the solution.

Molarity (M) =Numberofmolesofsolute1literofsolution

Explanation

Molality and molarity of pure water is calculated.

Given,

Density of water =0.977g/cm3Molar mass of water = 18.02g/mol

The mass of water is taken as 0.997kg since the density is 0.977g/cm3

The number of moles of water can be determined using the equation

Numberofmole=997g18.02g/mol=55

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