Biology 2e
2nd Edition
ISBN: 9781947172517
Author: Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher: OpenStax
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Textbook Question
Chapter 13, Problem 7RQ
Which recombination frequency corresponds to perfect linkage and violates the law of independent assortment?
- 0
- 0.25
- 0.50
- 0.75
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Which recombination frequency corresponds to perfect linkage and violates the law of independent assortment? a. 0 b. 0.25 c. 0.50 d. 0.75
Which recombination frequency corresponds to independent assortment and the absence of linkage? a. 0 b. 0.25 c. 0.50 d. 0.75
If two genes are unlinked the recombination frequency will be?
25%
50%
75%
100%
Chapter 13 Solutions
Biology 2e
Ch. 13 - Figure 13.3 In a test cross for two...Ch. 13 - Figure 13.4 Which of the following statements is...Ch. 13 - Figure 13.6 Which of the following statements...Ch. 13 - X-linked recessive traits in humans (or in...Ch. 13 - The first suggestion that chromosomes may...Ch. 13 - Which recombination frequency corresponds to...Ch. 13 - Which recombination frequency corresponds to...Ch. 13 - Which of the following codes describes position 12...Ch. 13 - In agriculture, polyploid crops (like coffee,...Ch. 13 - Assume a pericentric inversion occurred in one of...
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- The following recombination frequencies are calculated for four linked genes in the image attached: What is the frequency of crossing-over between A and D? a. 8% b. 6% c. 15% d. 11%arrow_forwardUsing Excel produce a plot that shows the decay of D over time (for 50 generations) for four different recombination frequencies: r = 0.5 (independent assortment) r = 0.25 r = 0.1 r = 0.01 *show graph and plot *arrow_forwardWhat would be the gene map for the following genes with known recombination frequencies? D and A is 5.1 cM, A and C is 15.8 cM, A and B is 7.8 cM, C and D is 10.7 cM, and C and B is 8.0 cM.arrow_forward
- Explain why the value of the recombination frequencybetween any two genes is limited to 50%.arrow_forwardThe following recombination frequencies are calculated for four linked genes: Genes Recombination Frequency A and B 2% B and C 17% C and D 4% A and C 15% B and D 13% What is the frequency of crossing-over between A and D? Select one: a. 8% b. 11% c. 6% d. 15%arrow_forwardA geneticist determines that the order of four genes on a specific chromosome is CABD because the recombination frequencies were 35% for C-D, 24% for A-D, 23% for B-D, and 10% for A-B. What has the geneticist constructed?arrow_forward
- Calculate the recombination frequency from the following data collected from a breeding experiment with butterflies. Parent 1: dihybrid, long legs and blue wings. Parent 2: double recessive, short legs and white wings Offspring: 50 long legs and white wings 200 long legs and blue wings 50 short legs and blue wings 200 short legs and white wings Recombination frequency is: Select one: a. 0.25 (25%) b. 0.10 (10%) c. 0.20 (20%) d. 0.33 (33%) e. 0.50 (50%)arrow_forwardIn the sample data from Sordaria shown in the picture: Count the total number of first and second segregations and calculate map units using equation below: (recombinant refers to second division segregation and non-recombinants are first division segregations)arrow_forwardIn a cross between mice the genotypes AB/ab x ab/ab, what is the recombination frequency if the progeny numbers are 72 AB/ab, 68 ab/ab, 17 Ab/ab, and 21 aB/ab? The alleles are shown for each chromosome, separated by a slash (/)arrow_forward
- There are three genes located on the same chromosome: G, H, and I. The recombination frequencies between each pair of genes were determined as follows: Gene Combination Recombination Frequency G/H 15.1% G/I 7.5% H/I 22.6% Which of the following gene maps demonstrate the correct sequence of these genes?arrow_forwardPLEASE WRITE ALL STEPS OUT. STEP BY STEP The recombination frequency between the A and B loci above is 32%. An offspring of the cross AABB x aabb is crossed in a test cross. How many progeny with the genotype Aabb would you expect out of 100 progeny from this test cross? O 16 O 32 68 34arrow_forwardFill the punnet square for just cross 2 and then do the chi square by using the observed values of cross 2 given in the picture:arrow_forward
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