   Chapter 13, Problem 82AE

Chapter
Section
Textbook Problem

# Consider the reaction Fe 3 + ( a q ) + SCN − ( a q ) ⇌ FeSCN 2 + ( a q ) How will the equilibrium position shift ifa. water is added, doubling the volume?b. AgNO3(aq) is added? (AgSCN is insoluble.)c. NaOH(aq) is added? [Fe(OH)3 is insoluble.]d. Fe(NO3)3(aq) is added?

Interpretation Introduction

Interpretation: The reaction of Fe3+(aq) and SCN is given. The shift in the position of equilibrium is to be predicted for the given conditions.

Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction.

According to Le Chatelier’s principle, “When equilibrium is subjected to change in variable, the shift in the equilibrium is produced in the direction that nullifies the effect of change”.

To determine: The shift of equilibrium when water is added and volume is doubled; when AgNO3(aq) is added; when NaOH(aq) is added; when Fe(NO3)3 is added.

Explanation

Explanation

(a)

The given reaction is,

Fe3+(aq)+SCN(aq)FeSCN2+(aq)

The addition of water to increase the volume does not affect the equilibrium because the concentration of reactant and product is unaffected.

Hence, the position of equilibrium does not get affected.

(b)

The given reaction is,

Fe3+(aq)+SCN(aq)FeSCN2+(aq)

The compound AgSCN is precipitated when AgNO3(aq) is added in the given reaction. Due to formation of AgSCN , the concentration of SCN(aq) is reduced in the reactant side.

Hence, to nullify the effect of this change, the equilibrium shifts to left side

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