   Chapter 13, Problem 88QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
16 views

# Although we: generally think of combustion reactions as involving oxygen gas, other rapid oxidation reactions are also referred to as combustions. For example, if magnesium metal is placed into chlorine gas, a rapid oxidation takes place, and magnesium chloride is produced.msp;  Mg ( s ) + Cl 2 ( g )   MgCl 2 ( s ) at Volume of chlorine gas, measured at STP, is required to react completely with 1 .0 2 g of magnesium?

Interpretation Introduction

Interpretation:

The volume of chlorine gas at STP should be calculated.

Concept Introduction:

According to ideal gas equation:

PV=nRT

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature.

The value of Universal gas constant can be taken as 0.082 L atm K1 mol1.

Mass of gas can be calculated from number of moles and molar mass as follows:

m=n×M

Here, n is number of moles, m is mass and M is molar mass.

Explanation

Given Information:

The mass of magnesium is 1.02 g.

Calculation:

The balanced chemical reaction is as follows:

Mg(s)+Cl2(g)MgCl2(s)

From the balanced chemical reaction, 1 mol of magnesium reacts with 1 mol of Cl2. To calculate the volume of oxygen gas, first calculate the number of moles of both C8H18 and oxygen gas.

n=mM

Molar mass of magnesium is 24.305 g/mol thus,

n=1.02 g24.305 g/mol=0.042 mol

Since, 1 mol of Mg reacts with 1 mol of Cl2 thus, 0

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