   Chapter 13, Problem 8PS

Chapter
Section
Textbook Problem

You want to prepare an aqueous solution of ethylene glycol, HOCH2CH2OH, in which the mole fraction of solute is 0.125. What mass of ethylene glycol, in grams, should you combine with 955 g of water? What is the molality of the solution?

Interpretation Introduction

Interpretation: The mass and molality of glycol to be identified.

Concept introduction:

Mole fraction: Amount of that component divided by the total amount of all of the components of the mixture ( nA +  nB +  n...).

Mole fraction of A (χA)= nA nA +  nB +  n...

Explanation

Given data:

Molefractionofethylene glycol(solute ,χglycol)= 0.125Mass ofglycol = ?Massofwater=955g

no.of moles (water) = massmolarmass=955 g 18.0158 g/mol = 53.009 mol

Mole fraction is the amount of that component divided by the total amount of all of the components of the mixture ( nA +  nB +  n...).

Mole fraction of A (χA)= nA nA +  nB +  n

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