   Chapter 13, Problem 8QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# ake the indicated pressure conversions.msp;  a .  14 . 9 psi to atmosphere b .  795 torr t 0  atmospheres c .  743 mm Hg to kilopascals d .  99 , 436 Pa to kilopascals

Interpretation Introduction

Interpretation:

The value of pressure14.9 psi should be converted to atmosphere.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Explanation

Since, 1 psi = 0.068046 atm

So,  14.9 psi = 14.9 psi × 0

Interpretation Introduction

Interpretation:

The value of pressure795 torr should be converted to atmosphere.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Interpretation Introduction

Interpretation:

The value of pressure743 mm Hgshould be converted to kilopascals.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Interpretation Introduction

Interpretation:

The value of pressure99, 436 Pa should be converted to kilopascals.

Concept Introduction:

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

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