   Chapter 13, Problem 95QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
14 views

# A sample, of helium gas occupies a volume of 25 . 2 mL at 95 ° C and a pressure of 392 mm Hg . Calculate the volume of the gas at STP.

Interpretation Introduction

Interpretation:

The volume of the gas at STP should be calculated Concept Introduction:

According to ideal gas equation:

PV=nRT

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature.

The value of Universal gas constant can be taken as 0.082 L atm K1 mol1.

Mass of gas can be calculated from number of moles and molar mass as follows:

m=n×M

Here, n is number of moles, m is mass and M is molar mass.

Explanation

Given Information:

The volume of helium gas is 25.2 mL, temperature is 95 C and pressure of gas is 892 mm Hg.

0.022 L

Calculation:

From given temperature, pressure and volume values, number of moles of He calculated as follows:

n=PVRT

Convert the given temperature from C to K:

0 C=273.15 K

Thus,

95 C=(95+273.15) K=368.15 K

Also, convert pressure from mm Hg to atm as follows:

1 atm=760 mm Hg

Thus,

892 mm Hg=892 mm Hg(1 atm760 mm Hg)=1.174 atm

Putting the values,

n=(1.174 atm)(25

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