   Chapter 13, Problem 99QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# Consider the following unbalanced chemical equation for the combination reaction of sodium metal and chlorine gas:msp;  Na ( s ) + Cl 2 ( g )   NaCl ( s ) at volume of chlorine gas. measured at STP, is necessary for the complete reaction of 4 . 81 g of sodium metal?

Interpretation Introduction

Interpretation:

The volume of chlorine gas at STP should be calculated.

Concept Introduction:

According to ideal gas equation:

PV=nRT

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature.

The value of Universal gas constant can be taken as 0.082 L atm K1 mol1.

Mass of gas can be calculated from number of moles and molar mass as follows:

m=n×M

Here, n is number of moles, m is mass and M is molar mass.

Explanation

Calculation:

The unbalanced chemical reaction is as follows:

Na(s)+Cl2(g)NaCl(s)

To balance the above reaction, give coefficient 2 to Na and Cl2 thus,

2Na(s)+Cl2(g)2NaCl(s)

To calculate the volume of chlorine gas, number of moles of sodium metal and chlorine gas should be calculated.

n=mM

Molar mass of sodium metal is 23 g/mol thus,

n=4.81 g23 g/mol=0.21 mol

From balanced chemical 2 mol of sodium metal reacts with 1 mol of chlorine gas thus, 1 mol will react with 0

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