   # You dissolve 1.0 mol of urea (H 2 NCONH 2 ) in 270 g of water. The mole fraction of urea is (a) 37×10 − 3 (b) 0.063 (c) 16 (d) 1.0 and its molality is (a) 1.0 (b) 3.7 (c) 0.063 (d) 0.27 ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 13.1, Problem 1RC
Textbook Problem
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## You dissolve 1.0 mol of urea (H2NCONH2) in 270 g of water. The mole fraction of urea is (a) 37×10− 3 (b) 0.063 (c) 16 (d) 1.0 and its molality is (a) 1.0 (b) 3.7 (c) 0.063 (d) 0.27

Interpretation Introduction

Interpretation: The Mole fraction and molality of urea is to be determined from the given option.

Concept introduction:

The number of moles of any substance can be determined using the equation

Numberofmole=GivenmassofthesubstanceMolarmass

Mole fraction: Amount of that component divided by the total amount of all of the components of the mixture ( nA +  nB +  n...) .

Mole fraction of A (χA)= nA nA +  nB +  n...

Molality (m): Molality is the number of moles of solute present in one kilogram of solvent.

Concentration (C, mol/kg) =  molality of solute = Amount of solute (mol)Mass of solvent (Kg)

### Explanation of Solution

• Mole fraction of urea

Reason for correct option

Given,

Number of moles of urea is 1.0mol

Molar mass of water is 18.02 g/mol

Mass of water is 270g

The number of moles of any substance can be determined using the equation

Numberofmole=GivenmassofthesubstanceMolarmass

Number of moles of water is,

nwater=270g18.02 g/mol=14.98mol

Mole fraction of urea is calculated,

Mole fraction of urea (χurea)= nurea nurea +  nwater =1mol(1mol+14.98mol)=0.063

Mole fraction of urea is 0

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