   Chapter 13.3, Problem 13.3SC ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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# trong>Exercise 13.3 A child blows a bubble that contains air at 28 ° C and has a volume of 23 cm 3 at I atm. As the bubble rises, it encounters a pocket of cold air (temperature 18 ° C ). If there is: no change in pressure, will the bubble get larger or smaller as the air inside cools to 18  ° C ? Calculate the new volume of the bubble.

Interpretation Introduction

Interpretation:

When the air inside the bubble cools to 18° C from an initial temperature of 28° C at a constant pressure, whether the bubble will get larger or smaller should be explained.

Also, the new volume of the bubble should be determined.

Concept Introduction:

Whether the bubble will get larger or smaller as well as the new volume of the bubble in this case can be determined using Charles law. Charles law states that the volume of a given amount of gas has direct relationship with temperature in Kelvin at constant pressure.

VTVT=constant

The increase in volume results in the increase in temperature and vice-versa.

The expression for calculating the initial and final volumes and temperatures at constant pressure is given by:

V1T1=V2T2.

Explanation

As can be seen from Charles law, the ratio of volume to temperature (V/T) is constant when the pressure is kept constant. So, when the temperature inside the bubble goes down to 18° C from 28° C, volume will also decrease accordingly to maintain V/T constant.

Now here, given

V1 = 23 cc

T1 = 28° C = (273+28) K = 301 K

T2 = 18° C = (273+18) K = 291 K

V2 = ? (need to be determined)

Using Charles equation,

V1T1=

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